简单的Java TCP服务器和PHP客户端问题

问题描述：

我试图在一个单一的端口上建立一个简单的TCP连接，用于作为TCP服务器的Java应用程序和作为客户端的PHP脚本。

I am trying to set up a simple TCP connection on a single port between a Java application that will act as the TCP server and a PHP scrip that will act as the Client.

我将为每个下面的代码，但问题是：
我可以连接和发送数据到Java服务器很好。我可以得到这些数据并打印出来。

I will post the code for each below, but the problem is: I can connect and send data to the Java server just fine. I can get that data and print it out. My problem arises in trying to send a response back to the php server.

当我注释掉最后一行phpecho socket_read（$ socket，14，PHP_NORMAL_READ）时，我的问题出现在尝试发送响应回到php服务器。 ;数据到达Java服务器就好了。当我添加该行时，数据甚至不会到达Java服务器。

When I comment out that last line of php "echo socket_read($socket, 14, PHP_NORMAL_READ);" The data gets to the Java server just fine. When I add that line back in, the data does not even get to the Java server.

因为这个，我假设我的问题有关我如何

Because of this, I am assuming my problem has something to do with how I am either sending the data from Java, or trying to get the data in PHP from the server.

这让我真的很累，任何帮助将非常感谢！

This has me really stumped, any help would be greatly appreciated!

Java服务器：

protected ServerSocket socket;
protected final int port = 9005;
protected Socket connection;
protected String command = new String();
protected String responseString = new String();


socket = new ServerSocket(port);


while(true)
{
    // open socket
    connection = socket.accept();
    // get input reader
    InputStreamReader inputStream = new InputStreamReader(connection.getInputStream());
    BufferedReader input = new BufferedReader(inputStream);
    // get output handler
    DataOutputStream response = new DataOutputStream(connection.getOutputStream());

    // get input
    command = input.readLine();

    // process input
    Logger.log("Command: " + command);
    responseString = command + " MC2 It Works!";

    // send response
    response.writeBytes(responseString);
    response.flush();
    response.close();
}

PHP客户端：

PHP Client:

$address = 'example.com'; // obviously not the address I am using
$port = 9005;
$message = "Test";

$socket = socket_create(AF_INET, SOCK_STREAM, getprotobyname('tcp'));

socket_connect($socket, $address, $port)

if(socket_send($socket, $message, strlen($message), MSG_EOF) != FALSE)
{
    echo socket_read($socket, 14, PHP_NORMAL_READ);
}

答

我想出了什么问题。当从Java服务器读回数据时，我只读一个块，一切都挂在其余的。数据需要在一个循环中读取以获得所有的数据。

SOLVED: Here is the solution I figured out what the problem was. When reading data back from the Java server, I was only reading one chunk and everything was hanging on the rest. The data needs to be read in a loop to get all of it.

此外，我发送到Java服务器的数据不是以一个新行或回车结束。

Also The data I was sending to the Java Server was not ending in a new line or carriage return.

以下重写的PHP客户端现在可以使整个事情正常工作

the following re-written PHP client now make the entire thing work nicely

$address = 'minecraft.kayoticgamer.com';
$port = 9005;

$socket = socket_create(AF_INET, SOCK_STREAM, getprotobyname('tcp'));
socket_connect($socket, $address, $port);

$message .= chr(10);

$status = socket_sendto($socket, $message, strlen($message), MSG_EOF, $address, $port);
if($status !== FALSE)
{
    $message = '';
    $next = '';
    while ($next = socket_read($socket, 4096))
    {
        $message .= $next;
    }

    echo $message;
}
else
{
    echo "Failed";
}

socket_close($socket);

简单的Java TCP服务器和PHP客户端问题

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