按照与另一个数组相同的顺序对数组进行排序

问题描述：

我有几个50多个这样的阵列。

I have a few arrays of 50+ names like this.

["dan", "ryan", "bob", "steven", "corbin"]
["bob", "dan", "steven", "corbin"]

我有另一个具有正确顺序的数组。请注意，上面的第二个数组不包含所有名称，但我仍然希望它遵循以下顺序：

I have another array that has the correct order. Note that the second array above does not include all of the names, but I still want it to follow the order of the following:

["ryan", "corbin", "dan", "steven", "bob"]

它没有逻辑顺序，它们只是按此顺序排列。对我来说有意义的是将每个数组与正确排序的数组进行比较。我想我看到有些人用PHP做这件事，但我找不到JavaScript解决方案。有谁知道怎么做？我已经尝试了几个小时而且我很难过。

There is no logical order to it, they are just in this order. What makes sense to me is to compare each array against the correctly ordered one. I think I saw some people doing this with PHP, but I was not able to find a JavaScript solution. Does anyone have any idea how to do this? I've been trying for a few hours and I'm stumped.

答

使用 indexOf（） 获取参考数组中每个元素的位置，并在比较函数中使用它。

Use indexOf() to get the position of each element in the reference array, and use that in your comparison function.

var reference_array = ["ryan", "corbin", "dan", "steven", "bob"];
var array = ["bob", "dan", "steven", "corbin"];
array.sort(function(a, b) {
  return reference_array.indexOf(a) - reference_array.indexOf(b);
});
console.log(array);

每次搜索参考数组对大型数组来说都是低效的。如果这是一个问题，您可以将其转换为将名称映射到位置的对象：

Searching the reference array every time will be inefficient for large arrays. If this is a problem, you can convert it into an object that maps names to positions:

var reference_array = ["ryan", "corbin", "dan", "steven", "bob"];
reference_object = {};
for (var i = 0; i < reference_array.length; i++) {
    reference_object[reference_array[i]] = i;
}
var array = ["bob", "dan", "steven", "corbin"];
array.sort(function(a, b) {
  return reference_object[a] - reference_object[b];
});
console.log(array);

按照与另一个数组相同的顺序对数组进行排序

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