将表单提交到弹出窗口？
问题描述：
我有一个脚本将表单提交到弹出窗口但不显示表单的操作（process.php），它不显示任何内容（空白窗口）。继承我的剧本：
I have a script that submits a form to a popup window but instead of displaying the form's action (process.php), it displays nothing (blank window). Heres my script:
function redirectOutput() {
var myForm = document.getElementById('formID');
var w = window.open('about:blank','Popup_Window','toolbar=0,scrollbars=0,location=0,statusb
ar=0,menubar=0,resizable=0,width=400,height=300,left = 312,top = 234');
myForm.target = 'Popup_Window';
return true;
}
答
它有效，但你有你的 window.open 突然出现换行符。
It works, but you have a newline suddenly in your window.open.
这对我来说很合适： http://jsfiddle.net/pimvdb/N3YSG/ 。
var myForm = document.getElementById('formID');
myForm.onsubmit = function() {
var w = window.open('about:blank','Popup_Window','toolbar=0,scrollbars=0,location=0,statusbar=0,menubar=0,resizable=0,width=400,height=300,left = 312,top = 234');
this.target = 'Popup_Window';
};