如何在方法模板中使用模板类型的按引用传递参数?

我目前正在努力获取以下代码进行编译.首先，头文件包含带有方法模板的类:

I am currently struggling to get the following code to compile. First the header file containing a class with a method template:

// ConfigurationContext.h

class ConfigurationContext
{
    public:
    template<typename T> T getValue(const std::string& name, T& default) const
        {
            ...
        }
}

我想在其他地方这样调用此方法:

Somewhere else I want to call this method like this:

int value = context.getValue<int>("foo", 5);

出现以下错误:

error: no matching function for call to 'ConfigurationContext::getValue(const std::basic_string<char, std::char_traits<char>, std::allocator<char> >&, int)'

我检查了明显的错误，例如缺少包含和类似的东西.但是一切似乎都是正确的.我试图删除模板类型参数的传递引用，如下所示:

I checked the obvious errors like missing includes and stuff like that. But everything seems to be right. I tried removing the pass-by-reference of the template type argument like this:

template<typename T> T getValue(const std::string& name, T default) const ...

然后它可以编译而没有任何错误，并且可以正常运行，但是我仍然想在这里传递引用...

Then it compiles without any errors and also runs fine, but I'd still like to pass in a reference here...

有人知道这里发生了什么以及如何使它工作吗?

Does anybody know whats happening here and how to make this work?