&“％tB&

问题描述：

System.out.format("%tB",12);

我应该得到一个十二月"，但是我得到一个很好的例外

I should get a "December" out of it, however i get a nice exception

Exception in thread "main" java.util.IllegalFormatConversionException: b != java.lang.Integer

这意味着我使用的语法是错误的. 我找不到在线说明%tB格式命令的参考. 有人帮忙澄清一下吗? 预先感谢.

It means the syntax I used is wrong. I cannot find any reference on line explaining the %tB formatting command. Is anybody help to clarify the matter? Thanks in advance.

答

来自 Formatter文档:

日期/时间-可以应用于能够编码的Java类型日期或时间:long，Long，Calendar和Date.

Date/Time - may be applied to Java types which are capable of encoding a date or time: long, Long, Calendar, and Date.

您可以通过使用长整数(例如12L)摆脱异常.但是请注意，格式化程序期望日期的整数表示形式(即，具有毫秒精度的Unix时间戳).

You can get rid of the exception by using a long integer such as 12L. But note that the formatter is expecting an integer representation of a date (i.e. a Unix timestamp with millisecond precision).

为了获得所需的内容，您可以尝试在1970年的一个月中手动构建一个近似的时间戳记:

In order to get what you want, you can try to manually build an approximate timestamp in a middle of a month in 1970 :

int month = 12;
int millisecondsInDay = 24*60*60*1000;
long date = ((month - 1L)*30 + 15)*millisecondsInDay;
System.out.format("%tB", date);

或者简单地使用Date对象:

System.out.format("%tB", new Date(0, 12, 0));

还请注意，您可以在没有Formatter 的情况下执行相同的操作:

Also note that you can do the same thing without Formatter :

java.text.DateFormatSymbols.getInstance().getMonths()[12-1];

请参见 DateFormatSymbols 了解更多信息.

See DateFormatSymbols for more information.

&“％tB&"格式化工作?

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