MFC->串口接收数据->显示为位图解决方案

MFC->串口接收数据->显示为位图
最近在研究飞思卡尔的上位机，看了很多上位机，用起来感觉还不错，想自己写一个，多学习一点儿VC，现在串口发送接收都木有问题了，但是如何把串口接收到的8位灰度数据（不包括BMP文件的信息头、调色板）变成位图显示出来呢……也就是说数据在数组里，怎么转化为位图显示出来呢，在这儿卡了好久了,好心人帮帮忙……感激不尽！！

------解决方案--------------------
给点代码参考：

C/C++ code


void CDrawbmpView::OnDraw(CDC* pDC)
{
    CDrawbmpDoc* pDoc = GetDocument();
    ASSERT_VALID(pDoc);
    pDoc->SetTitle("802D Simulator");
    // TODO: add draw code for native data here
    int hei=508;
    int wid=648;

    COLORREF color_table[16]={// 0x00bbggrr !
                0x000000,  //0
                0x000080,  //1
                0x008000,  //2
                0x008080,  //3
                0x800000,  //4
                0x800080,  //5
                0x808000,  //6
                0x808080,  //7
                0xC0C0C0,  //8
                0x0000FF,  //9
                0x00FF00,  //10
                0x00FFFF,  //11
                0xFF0000,  //12
                0xFF00FF,  //13
                0xFFFF00,  //14
                0xFFFFFF };//15
// open
    CFile if_hnd;
    if(!if_hnd.Open("snapbmp.dat",CFile::modeRead | CFile::shareExclusive))
    {
        AfxMessageBox("Cann't open image file!");
        return;
    }
// get mem
    unsigned fsize;
    fsize =if_hnd.GetLength();//
    BYTE *ScreenPtr1=0;
    ScreenPtr1=(BYTE *)new char[fsize];  //
// read all in
    if_hnd.Read(ScreenPtr1,fsize);//
// image data are in buffer
    if(if_hnd) if_hnd.Close();
#if 1 //def USE_API // fast way !
// make bitmap info
    LPBITMAPINFO pBMPinfo;
    pBMPinfo=(LPBITMAPINFO)new BYTE[sizeof(BITMAPINFOHEADER)+16*sizeof(RGBQUAD)];
    ZeroMemory(&pBMPinfo->bmiHeader,sizeof(BITMAPINFOHEADER));
    pBMPinfo->bmiHeader.biSize=sizeof(BITMAPINFOHEADER);
    pBMPinfo->bmiHeader.biBitCount=4;
    pBMPinfo->bmiHeader.biWidth=648;
    pBMPinfo->bmiHeader.biHeight=508;
    pBMPinfo->bmiHeader.biPlanes=1;
    pBMPinfo->bmiHeader.biSizeImage=648*508/2;
// copy colors
    for(int jj=0; jj<16; jj++)
    {// reversed !
        pBMPinfo->bmiColors[jj].rgbReserved=0;
        pBMPinfo->bmiColors[jj].rgbRed=(BYTE)(color_table[jj]  & 0x0000FF);
        pBMPinfo->bmiColors[jj].rgbGreen=(BYTE)((color_table[jj] & 0x00FF00) >> 8);
        pBMPinfo->bmiColors[jj].rgbBlue=(BYTE)((color_table[jj]   & 0xFF0000) >> 16);
    }
// draw bmp
    pDC->SetStretchBltMode(COLORONCOLOR);
    StretchDIBits(pDC->GetSafeHdc(),0,0,wid,hei,0,0,wid,hei,
                                    ScreenPtr1,
                                    pBMPinfo,
                                    DIB_RGB_COLORS,SRCCOPY);
// free
    delete pBMPinfo;
    delete [] ScreenPtr1;
    return;
#endif
// get mem, slow way !
    BYTE *ScreenPtr0=0;
    ScreenPtr0=(BYTE *)new char[fsize];  //
// Vertical flop
    int BytesOfLine=wid/2;// color 16: 648 pixels=324 bytes
    for(int kk=0; kk < hei; kk++)
    {
        memcpy(ScreenPtr0+kk*BytesOfLine,ScreenPtr1+fsize-(kk+1)*BytesOfLine,BytesOfLine);
    }
// data in ScreenPtr0 now !
    if (ScreenPtr1) delete [] ScreenPtr1;
// draw bmp 
    int bytepos,x,y,count,ofs;
    for (bytepos=0,x=0,y=0,count=0; count<hei*wid; count++)
    {
        if(!(count & 1))
        {
            ofs=(ScreenPtr0[bytepos]>>4) & 0x0F;
        }
        else
        {
            ofs=ScreenPtr0[bytepos++] & 0x0F;
        }
        SetPixel(pDC->m_hDC,x,y,color_table[ofs]);
        ++x;
        if(x>=wid)
        {
            x=0;
            y++;
        }
    }
    if(ScreenPtr0) delete []ScreenPtr0;
}

MFC->串口接收数据->显示为位图解决方案

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