更改iOS6中分组的uitableview的拐角半径
我尝试使用以下代码,但是没有运气.有人知道如何在iOS 6中执行此操作吗?我不想要创建自定义单元格.
I've tried using the following code but with no luck. Anybody know how to do this in iOS 6? I do not want to create a custom cell.
self.tableView.layer.cornerRadius = 5.0f;
[self.tableView setClipsToBounds:YES];
看来,实际发生的是此代码正在为整个视图而不是每个UITableViewSection创建一个拐角半径.这有道理吗?
It appears that what's actually happening is that this code is creating a corner radius for the entire view, not each individual UITableViewSection. Does this make sense?
我也尝试过[cell.layer setCornerRadius:3.0];
,但是也没有运气.我的UITableView的角仍然完全相同.
I have also tried [cell.layer setCornerRadius:3.0];
but also with no luck. The corners of my UITableView are still exactly the same.
您可以更改TableViewCell的backgroundView,创建UIView的子类并更改图层类:
You can change de backgroundView of the TableViewCell, create a subclass of UIView and change the layer class:
@interface BackgroundView : UIView
@end
@implementation BackgroundView
+ (Class)layerClass
{
return [CAShapeLayer class];
}
@end
稍后在cellForRowAtIndexPath中,您将执行以下操作:
later in cellForRowAtIndexPath you do something like this:
static NSString *CellIdentifier = @"CustomCell";
CustomCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath];
CGRect frame = cell.backgroundView.frame;
cell.backgroundView = [[BackgroundView alloc] initWithFrame:frame];
CGFloat corner = 20.0f;
UIBezierPath *path = [UIBezierPath bezierPathWithRoundedRect:cell.backgroundView.bounds byRoundingCorners:UIRectCornerAllCorners cornerRadii:CGSizeMake(corner, corner)];
CAShapeLayer *shapeLayer = (CAShapeLayer *)cell.backgroundView.layer;
shapeLayer.path = path.CGPath;
shapeLayer.fillColor = cell.textLabel.backgroundColor.CGColor;
shapeLayer.strokeColor = [UIColor lightGrayColor].CGColor;
shapeLayer.lineWidth = 1.0f;
return cell;
结果如下:
您可以修改所需的角点或创建其他路径.
You can modify the corners you want or create another path.
希望对您有帮助.