单击设备中的后退按钮时退出应用程序

问题描述：

我的应用程序中有3个活动.

There are 3 activities in my app.

Activity A(Main Page) -> Activity B -> Activity C.

点击活动C 中的提交按钮时，它将再次回到活动A .当我单击设备中的后退按钮以退出应用程序时，它将再次返回到活动C ，然后分别返回到 B 和 A ，出口.

When submit button in Activity C is clicked, it will back to Activity A again. When I click the back button in device to exit the app, it will back to Activity C again, then B and A , then only can exit.

是否有一种方法可以让应用程序在按后退"按钮时立即退出活动A中按下了设备?

Is there a way to let the app straight away exit when back button in device is pressed in Activity A?

我在活动A 中添加了以下代码，但问题是它仍然转到活动C ，而不是退出.

I add below code in Activity A, but the problem is it still goes to Activity C instead of exit.

boolean doubleBackToExitPressedOnce = false;

@Override
public void onBackPressed() {
    if (doubleBackToExitPressedOnce) {
        super.onBackPressed();
        return;
    }

    this.doubleBackToExitPressedOnce = true;
    Toast.makeText(this, "Please click BACK again to exit", Toast.LENGTH_SHORT).show();

    new Handler().postDelayed(new Runnable() {

        @Override
        public void run() {
            doubleBackToExitPressedOnce=false;                       
        }
    }, 2000);
}

答

感谢大家的回答和评论.我已经通过使用以下代码解决了该问题

Thanks guys for your answer and comment..I have solved it by using below code

 public void onBackPressed(){
        Intent a = new Intent(Intent.ACTION_MAIN);
        a.addCategory(Intent.CATEGORY_HOME);
        a.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        startActivity(a);

    }

单击设备中的后退按钮时退出应用程序

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