我如何才能找到在ASP.NET当前页面的（文件）的名字吗？

您的意思是说，你想找到当前执行对象的原始文件名？即，从控制内MyControl要检索 MyControlOnDisk.ascx ？在一般情况下，这个信息是在编译丢失，此外，许多网页和控制建立在局部类和它们从被编译成一个单一的组件是文件名。

You mean that you want to find the original filename of the object that is currently executed? I.e., from inside a control MyControl you want to retrieve MyControlOnDisk.ascx? In general, this information is lost upon compiling, and moreover, many pages and controls are built on partial classes and the filenames they're from are compiled into a single assembly.

对于一个页面，你可以使用以下，但只有当页面没有在内部重定向，不是实例从另一个页面的类，它不是一个母版页和你不是一个静态方法中：

For a page, you can use the following, but only if the page is not internally redirected, is not instantiated as a class from another page, it is not a master page and you're not inside a static method:

string currentPageFileName = new FileInfo(this.Request.Url.LocalPath).Name;

在控制的情况下，一般是不可能的，据我所知，（它编译距离），但也许有人能阐明这一些轻。

In the case of a control, it is generally not possible as far as I know (it is compiled away), but perhaps someone can shed some light on this.

的我想编写使用此名称的超 的

我假定你的意思写一个子类？如果你写一个超你只需创建一个虚拟的方法，并把它在你的子类（页）来实现。如果你的意思是创建一个子类，你可以把页面的类名，它看起来像这样：

I assume you mean to write a subclass? If you write a superclass you just create a virtual method and have it implemented in your subclass (the page). If you mean to create a subclass, you can take the classname of the page, which looks like this:

// current page
public partial class MyLovelyPage : System.Web.UI.UserControl

和使用它像这样从中得出：

and use it like this to derive from it:

public partial class NewDerivedPage : MyLovelyPage