如何获取我在 UIWebView 上点击的网址?
问题描述：
NSString *testString =[NSString stringWithFormat:@" <a href = \\\\ \"www.google.com\">Google</a>"];
[webView loadHTMLString:testString baseURL:nil];
我想在
-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType {
if ( inType == UIWebViewNavigationTypeLinkClicked ) {
[[UIApplication sharedApplication] openURL:inRequest.mainDocumentURL];
return NO;
}
return YES;
}
委托方法.当我在 webview 中单击 google 超链接时，它会给出
delegate method. When I click google hyperlink in webview it gives
网址:applewebdata://
URL: applewebdata://
请帮帮我.
答
你的问题不是很清楚你是想获取 webview 上的tapped url 还是 webview 的加载页面 url ,
You question is not very clear if you want to get the tapped url on webview or the webview's loaded page url ,
如果你想获取 webview 加载的页面 url，你可以使用 NSURLRequestObject，类似
If you want to get webview loaded page url you can use NSURLRequestObject,something like
NSString * url = [请求网址];
如果你想获得点击的链接 url ，你将不得不使用这个 java 脚本
If you want to get the clicked link url , you will have to use this java script
NSString *url = [webView stringByEvaluatingJavaScriptFromString:@window.location"];