在直方图matplotlib中绘制x-ticks

问题描述：

我想绘制给定名称的对应x. 我的意思是，对于foo，它必须以直方图的形式绘制[10,20,30]，并且所有foo，bar和baz都必须位于同一

I would like to plot the corresponding x for a given name. by that I mean, for foo it has to plot [10,20,30] in the form of a histogram and all foo, bar, baz need to be in the same graph.(I don't require 3d :) )

import pylab as P
name = ['foo', 'bar', 'baz']
x  = [[10,20,30],[40,50,60],[70,80,90]]

P.figure()
P.hist(x, 10,  histtype='bar',
                color=['crimson', 'burlywood', 'chartreuse'],
                label=['Crimson', 'Burlywood', 'Chartreuse'])

P.show()

答

希望这对您有帮助:

from matplotlib import pyplot as plt
import numpy as np

names = ['foo', 'bar', 'baz']
x  = [[10, 20, 30], [40, 50, 60], [70, 80, 90]]
colors = ['crimson', 'burlywood', 'chartreuse']

y = zip(*x)
groups = len(x)
members = len(y)
pos = np.arange(groups)
width = 1. / (1 + members)

fig, ax = plt.subplots()    
for idx, (serie, color) in enumerate(zip(y, colors)):
    ax.bar(pos + idx * width, serie, width, color=color)

ax.set_xticks(pos + width)
ax.set_xticklabels(names)

plt.show()

在直方图matplotlib中绘制x-ticks

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