绘制在Libgdx渐变
好吧，我有这个code
Ok I have this code
@Override
public void render() {
// do not update game world when paused
if (!paused) {
// Update game world by the time that has passed
// since last render frame
worldController.update(Gdx.graphics.getDeltaTime());
}
// Sets the clear screen color to: Cornflower Blue
Gdx.gl.glClearColor(0x64/255.0f, 0x95/255.0f, 0xed/255.0f,
0xff/255.0f);
// Clears the screen
Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT);
// Render game world to screen
worldRenderer.render();
}
和它绘制一个浅蓝色背景到屏幕上。我试图创建一个梯度，它从一个深蓝色的顶部，以向底部浅蓝色。有没有一种简单的方法来做到这一点？我是新来Libgdx，和OpenGL所以我想从一本书来学习，但我似乎无法找到这个问题的答案之一。我听说画一个大广场和具有顶点不同颜色的，但我不确定如何做到这一点。
And it draws a light blue background onto the screen. I am attempting to create a gradient that goes from a dark blue at the top, to a light blue towards the bottom. Is there a simple way to do this? I'm new to Libgdx, and OpenGL so i'm trying to learn from a book but I can't seem to find the answer to this one. I've heard of drawing a big square and having the vertices different colors, but I'm unsure of how to do this.
在libGDX中，ShapeRenderer对象包含一个的drawRect（）方法，它的参数为它的位置和大小还有四种颜色。这些颜色被转换为4角梯度。如果你想有一个垂直梯度，才使上角一种颜色和底角另一种颜色。事情是这样的：
In libGDX, the ShapeRenderer object contains a drawRect() method that takes arguments for its position and size as well as four colors. Those colors are converted to a 4-corners gradient. If you want a vertical gradient, just make the top corners one color and the bottom corners another color. Something like this:
shapeRenderer.filledRect(x, y, width, height, lightBlue, lightBlue, darkBlue, darkBlue);
这是为ShapeRenderer的API：
From the API for ShapeRenderer:
四色参数指定颜色为左下，右下，右上和矩形的左上角，允许您创建渐变。
The 4 color parameters specify the color for the bottom left, bottom right, top right and top left corner of the rectangle, allowing you to create gradients.