错误1'classlibrary3.trunk.trunk（）'由于其保护级别而无法访问
namespace ClassLibrary3
{
class SIPtrunk : Trunk
{
private int IPSigRemote; // Destination Point Code
private int Capacity; // Nombre de circuits * 32
private string GroupDirection; // IN, OUT, Bi-Directionnel
void GetSIPtrunk()
{
}
void GetSIPtrunk(int ips, int capacity, string groupdirection)
{
this.Capacity = capacity;
this.GroupDirection = groupdirection;
this.IPSigRemote = ips;
}
}
}
我尝试过：
命名空间ClassLibrary3
{
class SIPtrunk：Trunk //问题在这里
{
private int IPSigRemote; //目的地点代码
private int容量; // Nombre de circuits * 32
private string GroupDirection; // IN，OUT，Bi-Directionnel
void GetSIPtrunk（）
$
}
void GetSIPtrunk（int ips ，int capacity，string groupdirection）
{
this.Capacity = capacity;
this.GroupDirection = groupdirection;
this.IPSigRemote = ips;
}
}
}
What I have tried:
namespace ClassLibrary3
{
class SIPtrunk : Trunk// the problem is here
{
private int IPSigRemote; // Destination Point Code
private int Capacity; // Nombre de circuits * 32
private string GroupDirection; // IN, OUT, Bi-Directionnel
void GetSIPtrunk()
{
}
void GetSIPtrunk(int ips, int capacity, string groupdirection)
{
this.Capacity = capacity;
this.GroupDirection = groupdirection;
this.IPSigRemote = ips;
}
}
}
正如我之前提到的那样：
As I said when you asked this earlier:
想一想：如果B类派生自A类，那么B类包含A类的所有属性，方法和字段以及它自己添加的任何内容。
因此，要在您的应用中使用B类，您的代码必须能够访问所有A类功能，无论它在何处应用程序。
现在假设你有两个Assemblies，一个包含A和B类，另一个只尝试使用B类。如果无法从第二个程序集访问A类，因为它被标记为protected，internal，甚至是private，但是B被声明为public，那么您编写的使用它的代码根本无法访问A类 - 所以它不会知道B级真正包含和能够做什么 - 结果你得到不一致的可访问性错误。
要么改变A类的访问权限，要么为B类，或者将类A实例封装在B中，而不是从它派生。
Think about it: if class B is derived from class A then class B contains all the properties, methods, and fields of class A as well as any it adds itself.
So to use class B in your app, your code must be able to access all class A features regardless of where it is in the app.
Now suppose you have two Assemblies, one containing classes A and B, and the other trying to use class B only. If class A is not accessible from the second assembly because it is marked as protected, internal, or even private but B is declared as public, the code you write to use it can't access class A at all - so it doesn't know what class B is truly containing and capable of - and you get an "inconsistent accessibility" error as a result.
Either change the access for class A, or for class B, or encapsulate the class A instance in B instead of deriving from it.
除非Trunk也是 public ，否则这将不起作用。
Unless Trunk is also public this will not work.