如何在一个月内获得星期五的日期

问题描述：

如何在一个月内获得星期五的约会？假设7月份有4个星期五。我想要检索日期。我不使用任何数据库表。请帮帮我。

How can I get Friday dates in a month? Suppose in July there are 4 Friday. I want to retrieve the dates. I don't use any database table. Please help me.

答

试试这个.. :)

try this.. :)

declare @DateFrom datetime,@DateTo datetime
set @DateFrom='23 Mar 2014'
set @DateTo='26 Jun 2014'

;WITH CTEQuery AS (
			  SELECT CAST(@DateFrom AS DATETIME) AS dt
			  UNION ALL
			  SELECT DATEADD(dd, 1, dt)
			   FROM CTEQuery s
			   WHERE DATEADD(dd, 1, dt) <= CAST(@DateTo AS DATETIME)
			   ),sampleData as(
select dt,datename(WEEKDAY,dt)as [DayName] from CTEQuery )
select * from sampleData where [DayName]='Friday'

你必须从代码后面传递@ DateFrom 和@ DateTo ，你将ge那些星期五之间的日期日期..：）

you have to just pass @DateFrom and @DateTo from code behind and you will get all friday dates between there dates.. :)

首先，我假设你'使用 SQL Server 。这是一个示例（查询应该在 SQL Server 2005 或更高版本中工作）：

Hi,

First of all, I'm assuming that you're using SQL Server. Here's an example (the query should work in SQL Server 2005 or above):

DECLARE @Year      VARCHAR(4),
        @Month     VARCHAR(3),
        @FirstDate DATETIME,
        @LastDate  DATETIME;

SET @Year = '2014';
SET @Month = '07'; -- '07' or 'Jul'
SET @FirstDate = (SELECT CAST(( @Year + @Month + '01' ) AS DATETIME));
SET @LastDate = DATEADD(DAY, -1, ( DATEADD(MONTH, 1, @FirstDate) ));

;WITH Fridays([Date])
     AS (SELECT [Date] = @FirstDate
         UNION ALL
         SELECT [Date] = DATEADD(DAY, 1, [Date])
         FROM   Fridays
         WHERE  [Date] < @LastDate)
SELECT [Date]
FROM   Fridays
WHERE  DATENAME(WEEKDAY, [Date]) = 'Friday';

注意：考虑到输入参数和 SQL Server 的版本，可以（应该）改进此查询。

结果：

Note: This query could (should) be improved considering your input parameters and version of the SQL Server.

Result:

Date
2014-07-04 00:00:00.000
2014-07-11 00:00:00.000
2014-07-18 00:00:00.000
2014-07-25 00:00:00.000

如果您需要进一步帮助，请与我们联系。

Please let me know if you need further assistance.

DECLARE @StartDate date = '2014-07-01'
DECLARE @EndDate date = '2014-07-31' 
CREATE TABLE #tblGetFriday ([Friday] Date)

WHILE @StartDate <> CONVERT(date,@EndDate)
BEGIN
	IF((SELECT UPPER(DATENAME(dw, @StartDate))) = 'FRIDAY')
	BEGIN	
		INSERT INTO #tblGetFriday SELECT @StartDate As Fridays
	END
	
	
	SET @StartDate = DATEADD(Day,1,@StartDate)
END

SELECT * FROM #tblGetFriday
DROP TABLE #tblGetFriday

如何在一个月内获得星期五的日期

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