摆动:将功能键(F2)设置为加速键

问题描述：

我有一个菜单项重命名"，为此将F2设置为加速器.确实，显示菜单时，在重命名"旁边会显示一个小"F2"指示.

I have a menu item, "rename", for which F2 is set as an accelerator. Indeed when the menu is displayed there a little "F2" indication next to "rename".

遗憾的是，这不起作用.该加速器不会触发任何响应.当我将加速器更改为CTRL + F2时，它将起作用.

Sadly, this does not work. This accelerator triggers no response. When I change the accelerator to CTRL+F2 - it works.

似乎我应该使用InpoutMpa/ActionMap.这样做的问题是我希望它可以在应用程序中的任何地方工作，因此我试图将其与顶级JFrame关联.但是，JFrame没有getInputMap()方法.

It seems that I should use an InpoutMpa/ActionMap. The problem with that is that I want this to work everywhere in the app so I am trying to associate it with the top-level JFrame. But, JFrame does not have a getInputMap() method.

迷失了.

[已添加]

     ks = KeyStroke.getKeyStroke(KeyEvent.VK_F2, 0);
     JMenuItem mi = new JMenuItem("Rename");
     mi.setAccelerator(ks);
     mi.addActionListener(action);

答

我知道这是一个旧线程，但是我在与原始海报完全相同的事情上苦苦挣扎，并找到了解决方案.JFrame本身没有getInputMap方法，但其根窗格却有.因此，您必须改为使用"getRootPane.getInputMap".

I know this is an old thread, but I struggled with the exact same thing as the original poster and found the solution. The JFrame itself doesn't have a getInputMap method, but its root pane does. So you have to use "getRootPane.getInputMap" instead.

示例代码:

public class ApplicationFrame extends JFrame {
    private AbstractAction f2Action = new AbstractAction() {
        private static final long serialVersionUID = 1L;

        public void actionPerformed(ActionEvent e) {
            // Do something useful
        }
    };

    public ApplicationFrame() {

        InputMap inputMap = getRootPane().getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW);
        ActionMap actionMap = getRootPane().getActionMap(); 

        inputMap.put(KeyStroke.getKeyStroke("F2"), "f2Action");
        actionMap.put("f2Action", f2Action);

    }
}

摆动:将功能键(F2)设置为加速键

相关推荐