如何使用python的networkx模块从节点列表生成完全连接的子图

问题描述：

我需要从要连接的节点列表开始，使用 networkx 生成完全连接的子图.基本上，我希望传递给函数的列表中的所有节点都相互连接.

I need to generate a fully connected subgraph with networkx, starting from the list of nodes I want to connect. Basically, I want all the nodes in the list I pass to the function to be all connected with each other.

我想知道是否有内置函数来实现这一点(我没有找到)? 还是我应该考虑一些算法?

I wonder if there is any built-in function to achieve this (which I haven't found)? Or should I think of some algorithm?

非常感谢.

答

我不知道执行此操作的任何方法，但是您可以轻松模仿networkx的complete_graph()方法并稍作更改(几乎像内置方法一样) ):

I don't know of any method which does this, but you can easily mimic the complete_graph() method of networkx and slightly change it(almost like a builtin):

import networkx
import itertools

def complete_graph_from_list(L, create_using=None):
    G = networkx.empty_graph(len(L),create_using)
    if len(L)>1:
        if G.is_directed():
            edges = itertools.permutations(L,2)
        else:
            edges = itertools.combinations(L,2)
        G.add_edges_from(edges)
    return G

S = complete_graph_from_list(["a", "b", "c", "d"])
print S.edges()

如何使用python的networkx模块从节点列表生成完全连接的子图

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