删除从另一个指针分配的指针，我应该再次删除另一个指针吗?

所以，这是我的例子来解释这个问题

so, here is my example to explain this question

void * p1;
int * p2, * p3;

p2 = new int;
p1 = p2;
p3 = (int *) p1;

要释放内存，以下3行是否彼此相等?

to free the memory, are the following 3 lines equivalent to each other?

delete p2;
delete p3;
delete (int *) p1;

我使用这种方法的原因是，我想在函数之间传递一个指针，而又不知道其类型，例如，我定义了一个void指针，并通过调用其他函数来更改其值，如下所示:

the reason i am using such is that i want to pass a pointer between functions without knowing its type, for instance i define a void pointer and changes its value by calling other functions as follow:

void * p1;
func1(p1); //in this function, p2 = new int and  p1 is assigned as p1 = p2;
func2(p1); //in this function, p1 is assigned to another pointer: int * p3 = (int *)p1;

然后，我打电话给func3释放内存

then, i called func3 to release the memory

func3(p1); //delete int * p1

在调用func3之后，我是否还要处理func1中的p2吗?

after calling func3, do i have to deal with p2 in func1 anymore?

谢谢！