如何手动创建树状图（或“ hclust”）对象？ （在R中）
我给了我一个树状图作为图像。由于它不是很大，因此我可以手工将其构造为R对象。
I have a dendrogram given to me as images. Since it is not very large, I can construct it "by hand" into an R object.
所以我的问题是如何手动创建树状图（或 hclust ）对象，当我所有的都是树状图图像时？
So my question is how do I manually create a dendrogram (or "hclust") object when all I have is the dendrogram image?
我看到有一个名为 as.dendrogram的函数，但是我找不到一个示例有关如何使用它的信息。
I see that there is a function called "as.dendrogram" But I wasn't able to find an example on how to use it.
（ps：这篇帖子是我在）
(p.s: This post is following my question from here)
非常感谢，
Tal
Many thanks, Tal
我认为您最好创建一个 hclust 对象，并且然后使用 as.dendrogram 将其转换为树状图，然后尝试直接创建树状图。查看？hclust 帮助页面，以了解 hclust 对象的元素的含义。
I think you are better of creating an hclust object, and then converting it to a dendrogram using as.dendrogram, then trying to create a dendrogram directly. Look at the ?hclust help page to see the meaning of the elements of an hclust object.
这里是一个简单的示例，其中有四个叶子A，B，C和D，先组合AB，再组合CD，最后组合AB-CD：
Here is a simple example with four leaves A, B, C, and D, combining first A-B, then C-D, and finally AB-CD:
a <- list() # initialize empty object
# define merging pattern:
# negative numbers are leaves,
# positive are merged clusters (defined by row number in $merge)
a$merge <- matrix(c(-1, -2,
-3, -4,
1, 2), nc=2, byrow=TRUE )
a$height <- c(1, 1.5, 3) # define merge heights
a$order <- 1:4 # order of leaves(trivial if hand-entered)
a$labels <- LETTERS[1:4] # labels of leaves
class(a) <- "hclust" # make it an hclust object
plot(a) # look at the result
#convert to a dendrogram object if needed
ad <- as.dendrogram(a)