计算两个整数之间的和

问题描述：

我有一种方法可以解决两个数字之间的和，但是如果第一个数字大于第二个数字，它将不会显示任何内容，但是如果我添加一个if语句，则该方法将出错，提示无法访问代码

public int sum(int sum1，int sum2)
{

int sum0;
sum0 =(sum1 + sum2)*(sum1-sum2 + 1)/2;

返回sum0;

}

i have a method that solves the sum between two numbers but if the first number is greater than the second it wont display anything but if i add an if statement i get an error for the method saying unreachable code

public int sum(int sum1,int sum2)
{

int sum0;
sum0=(sum1+sum2)*(sum1-sum2+1)/2;

return sum0;

}

答

它不在此方法中.请使用调试器进行检查.捕获该线程中的所有异常，看看会发生什么；它应该给您确切的位置.

方法的主体应该只是一行:

It''s not in this method. Please check up, using the debugger. Catch all exceptions in this thread and see what happens; it should give you exact location.

And the body of your method should be just one line:

return (sum1 + sum2) * (sum1 - sum2 + 1) / 2;

当然，您写的不是一个错误，但是看起来很奇怪……

—SA

Of course, what you write is not a mistake, but looks weird…

—SA

尝试一下.

try this.

public static int sum(int sum1,int sum2)
	{

	int sum  = sum1 > sum2 ? (sum1+sum2)*(sum1-sum2+1)/2 : (sum1+sum2)*(sum2-sum1+1)/2;
	
	return sum;


	}

计算两个整数之间的和

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