如何解析保存日期为“ Oct 1,2015 12:00:00 AM”格式的字符串?
问题描述:
String dateString = "Oct 1, 2015 12:00:00 AM";
try {
SimpleDateFormat sdf = new SimpleDateFormat("");
sdf.parse(dateString);
} catch (ParseException e) {
e.printStackTrace();
}
答
SimpleDateFormat
Javadoc包含一个表,该表说(部分)
The SimpleDateFormat
Javadoc includes a table that says (in part)
Letter Date or Time Component Presentation Examples
G Era designator Text AD
y Year Year 1996; 96
Y Week year Year 2009; 09
M Month in year Month July; Jul; 07
w Week in year Number 27
W Week in month Number 2
D Day in year Number 189
d Day in month Number 10
F Day of week in month Number 2
E Day name in week Text Tuesday; Tue
u Day number of week (1 = Monday, ..., 7 = Sunday) Number 1
a Am/pm marker Text PM
H Hour in day (0-23) Number 0
k Hour in day (1-24) Number 24
K Hour in am/pm (0-11) Number 0
h Hour in am/pm (1-12) Number 12
m Minute in hour Number 30
s Second in minute Number 55
S Millisecond Number 978
我想您想要的格式如 MMM dd,yyyy hh:mm:ss a
。
I think you want a format like MMM dd, yyyy hh:mm:ss a
. Something like,
String userDateFormat = "MMM dd, yyyy hh:mm:ss a";
String dateString = "Oct 1, 2015 12:00:00 AM";
DateFormat sdf = new SimpleDateFormat(userDateFormat);
try {
Date date = sdf.parse(dateString);
System.out.println(sdf.format(date));
} catch (ParseException e) {
e.printStackTrace();
}
哪个输出
Oct 01, 2015 12:00:00 AM