将字符串日期格式从“17-Nov-2011”转换为到“11/17/11”
问题描述:
我有这个代码将日期字符串数组从2011年11月17日的格式转换为11/17/11:
I have this code that converts an array of date strings from a format of 17-Nov-2011 to 11/17/11:
def date_convert dates
months = { 'Jan' => 1, 'Feb' => 2, 'Mar' => 3, 'Apr' => 4,
'May' => 5, 'Jun' => 6, 'Jul' => 7, 'Aug' => 8,
'Sep' => 9, 'Oct' => 10, 'Nov' => 11, 'Dec' => 12 }
new_dates = []
dates.each do |date|
date_split = date.split('-')
month = months[date_split[1]]
day = date_split[0]
year = date_split[2][-2, 2]
new_dates.push ("#{month}/#{day}/#{year}")
end
new_dates
end
有没有更好的,可能内置的方法来使用Ruby进行这种转换?我正在学习Ruby,所以任何其他的方法,将不胜感激。
Is there a better, possibly built in, way to make this conversion with Ruby? I am learning Ruby so any other approach to this would be much appreciated.
答
使用内置 Time.parse
和 Time#strftime
函数
Use the built-in Time.parse
and Time#strftime
functions.
require 'time'
time = Time.parse("17-Nov-2011")
time.strftime("%m/%d/%y")
# => "11/17/11"