PHP - 从JSON中提取数据

问题描述：

I have a JSON file where I'm struggling getting the data out. Here is the JSON.

{"data":[
        {"tag":"operatingrevenue","value":215639000000.0},
        {"tag":"totalrevenue","value":215639000000.0},
        {"tag":"operatingcostofrevenue","value":131376000000.0},
        {"tag":"totalcostofrevenue","value":131376000000.0},
        {"tag":"totalgrossprofit","value":84263000000.0},
        {"tag":"sgaexpense","value":14194000000.0},
        {"tag":"rdexpense","value":10045000000.0},
        {"tag":"totaloperatingexpenses","value":24239000000.0},
        {"tag":"totaloperatingincome","value":60024000000.0},
        {"tag":"otherincome","value":1348000000.0},
        {"tag":"totalotherincome","value":1348000000.0},
        {"tag":"totalpretaxincome","value":61372000000.0},
        {"tag":"incometaxexpense","value":15685000000.0},
        {"tag":"netincomecontinuing","value":45687000000.0},
        {"tag":"netincome","value":45687000000.0},
        {"tag":"netincometocommon","value":45687000000.0},
        {"tag":"weightedavebasicsharesos","value":5470820000.0},
        {"tag":"basiceps","value":8.35},
        {"tag":"weightedavedilutedsharesos","value":5500281000.0},
        {"tag":"dilutedeps","value":8.31},
        {"tag":"weightedavebasicdilutedsharesos","value":5471500000.0},
        {"tag":"basicdilutedeps","value":8.35},
        {"tag":"cashdividendspershare","value":2.18}]

I'm converting it to an array using

$data = json_decode($jsondata, true);

I can then pull the data by:

$operatingRevenue = $data['data'][0]['value'];
$totalrevenue = $data['data'][1]['value'];

etc, however, I want to use the tag name and not just the order just in case the order changes in the JSON. Something like

$operatingRevenue = $data['data']['operatingRevenue'];

我有一个JSON文件，我正在努力获取数据。这是JSON。 p>

  {“data”：[
 {“tag”：“operatingrevenue”，“value”：215639000000.0}，
 {“tag”：  “totalrevenue”，“value”：215639000000.0}，
 {“tag”：“operatingcostofrevenue”，“value”：131376000000.0}，
 {“tag”：“totalcostofrevenue”，“value”：131376000000.0}，
 {  “tag”：“totalgrossprofit”，“value”：84263000000.0}，
 {“tag”：“sgaexpense”，“value”：14194000000.0}，
 {“tag”：“rdexpense”，“value”：10045000000.0}  ，
 {“tag”：“totaloperatingexpenses”，“value”：24239000000.0}，
 {“tag”：“totaloperatingincome”，“value”：60024000000.0}，
 {“tag”：“otherincome”，“value  “：1348000000.0}，
 {”tag“：”totalotherincome“，”value“：1348000000.0}，
 {”tag“：”totalpretaxincome“，”value“：61372000000.0}，
 {”tag“：”incometaxexpense  “，”“value”：15685000000.0}，
 {“tag”：“netincomecontinuing”，“value”：45687000000.0}，
 {“tag”：“netincome”，“value”：45687000000.0}，
 {“tag  “：”netincometocommon“，”value“：45687000000.0}，
 {”tag  “：”weightedavebasicsharesos“，”value“：5470820000.0}，
 {”tag“：”basiceps“，”value“：8.35}，
 {”tag“：”weightedavedilutedsharesos“，”value“：5500281000.0}，\  n {“tag”：“dilutedeps”，“value”：8.31}，
 {“tag”：“weightedavebasicdilutedsharesos”，“value”：5471500000.0}，
 {“tag”：“basicdilutedeps”，“value”：  8.35}，
 {“tag”：“cashdividendspershare”，“value”：2.18}] 
  code>  pre> 
 
 我正在使用 p将其转换为数组 > 
 
 
  $ data = json_decode（$ jsondata，true）; 
  code>  pre> 
 
 然后我可以通过以下方式提取数据： p  > 
 
 
  $ operatingRevenue = $ data ['data'] [0] ['value']; 
 $ totalrevenue = $ data ['data'] [1] ['value']  ; 
  code>  pre> 
 
 等，但是，我希望使用标记名称而不仅仅是订单，以防订单在JSON中发生变化。 类似 p> 
 
 
  $ operatingRevenue = $ data ['data'] ['operatingRevenue']; 
  code>  pre> 
  div>

答

Iterate the $data array, and set the key of a new element in the array to the tag element, and it's value to the value element.

foreach($data['data'] as $v)
    $array[$v['tag']] = $v['value'];

$array contains what you want, access like this: $array['operatingRevenue']

答

Iterate $data and use array_push. Read it here. https://www.w3schools.com/php/func_array_push.asp

$data = json_decode($jsondata, true);
$datas = [];
foreach($data['data'] as $val){
   array_push($datas,["tag"=>$val['tag'],"value"=>$val['tag']])
}

PHP - 从JSON中提取数据

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