启动嵌入式Jetty服务器的最短代码

问题描述：

我正在编写一些示例代码，其中将启动嵌入式Jetty服务器.服务器必须仅加载一个servlet，将所有请求发送到servlet并在localhost:80上侦听

I'm writing some example code where an embedded Jetty server is started. The server must load exactly one servlet, send all requests to the servlet and listen on localhost:80

到目前为止，我的代码:

My code so far:

static void startJetty() {
        try {
            Server server = new Server();

            Connector con = new SelectChannelConnector();
            con.setPort(80);
            server.addConnector(con);

            Context context = new Context(server, "/", Context.SESSIONS);
            ServletHolder holder = new ServletHolder(new MyApp());
            context.addServlet(holder, "/*");

            server.start();
        } catch (Exception ex) {
            System.err.println(ex);
        }

    }

我可以用更少的代码/行来做同样的事情吗? (使用Jetty 6.1.0).

Can i do the same with less code/lines ? (Jetty 6.1.0 used).

答

static void startJetty() {
    try {
        Server server = new Server();
        Connector con = new SelectChannelConnector();
        con.setPort(80);
        server.addConnector(con);
        Context context = new Context(server, "/", Context.SESSIONS);
        context.addServlet(new ServletHolder(new MyApp()), "/*");
        server.start();
    } catch (Exception ex) {
        System.err.println(ex);
    }
}

删除了不必要的空格，并内联移动了ServletHolder创建.删除了5行.

Removed unnecessary whitespace and moved ServletHolder creation inline. That's removed 5 lines.

启动嵌入式Jetty服务器的最短代码

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