将base64转换为base62(不带特殊字符)

问题描述：

我想在URL中传递河豚加密的字符串，并希望像base64一样对它进行编码，但是如果没有任何特殊字符，像base62这样的东西会很棒(0-9a-zA-Z).所以我想做的是使用base64_encode转换河豚加密的字符串，并将base64转换为base62.

I want to pass a blowfish encrypted string in a URL, and want to encode it like base64, but without any special character, something like base62 would be great (0-9a-zA-Z). So what I'm trying to do is converting the blowfish encrypted string using base64_encode, and convert base64 to base62.

我知道有关如何使base64网址安全的解决方案，但是我真的不希望字符串中有任何特殊字符.convert_base()仅适用于以36为底的基数，数学扩展可以转换为以62为底的基数.

I know about solutions how to make base64 url-safe, but I really don't want any special character in the string. convert_base() only works with base up to 36, the math extensions can convert up to base 62.

有人知道如何使用PHP将base64字符串转换为base62吗?

答

function base62encode($data) {
    $outstring = '';
    $l = strlen($data);
    for ($i = 0; $i < $l; $i += 8) {
        $chunk = substr($data, $i, 8);
        $outlen = ceil((strlen($chunk) * 8)/6); //8bit/char in, 6bits/char out, round up
        $x = bin2hex($chunk);  //gmp won't convert from binary, so go via hex
        $w = gmp_strval(gmp_init(ltrim($x, '0'), 16), 62); //gmp doesn't like leading 0s
        $pad = str_pad($w, $outlen, '0', STR_PAD_LEFT);
        $outstring .= $pad;
    }
    return $outstring;
}

function base62decode($data) {
    $outstring = '';
    $l = strlen($data);
    for ($i = 0; $i < $l; $i += 11) {
        $chunk = substr($data, $i, 11);
        $outlen = floor((strlen($chunk) * 6)/8); //6bit/char in, 8bits/char out, round down
        $y = gmp_strval(gmp_init(ltrim($chunk, '0'), 62), 16); //gmp doesn't like leading 0s
        $pad = str_pad($y, $outlen * 2, '0', STR_PAD_LEFT); //double output length as as we're going via hex (4bits/char)
        $outstring .= pack('H*', $pad); //same as hex2bin
    }
    return $outstring;
}

$str62 = base62_encode(base64_decode($str64)) // $str64 = our string base64 encoded

所有功劳归于 Marcus Bointon .

将base64转换为base62(不带特殊字符)

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