如何获得的比特阵列中的结构？

我琢磨（因此正在寻找一种方式来学习这一点，并没有更好的解决办法）是否有可能得到位的数组中的结构。

I was pondering (and therefore am looking for a way to learn this, and not a better solution) if it is possible to get an array of bits in a structure.

让我用一个例子证明。试想一下，这样的code：

Let me demonstrate by an example. Imagine such a code:

#include <stdio.h>

struct A
{
    unsigned int bit0:1;
    unsigned int bit1:1;
    unsigned int bit2:1;
    unsigned int bit3:1;
};

int main()
{
    struct A a = {1, 0, 1, 1};
    printf("%u\n", a.bit0);
    printf("%u\n", a.bit1);
    printf("%u\n", a.bit2);
    printf("%u\n", a.bit3);
    return 0;
}

在此code，我们装在一个struct 4各个位。它们可以单独进行访问，留下位操作的作业到编译器​​。我想知道是，如果这样的事情是可能的：

In this code, we have 4 individual bits packed in a struct. They can be accessed individually, leaving the job of bit manipulation to the compiler. What I was wondering is if such a thing is possible:

#include <stdio.h>

typedef unsigned int bit:1;

struct B
{
    bit bits[4];
};

int main()
{
    struct B b = {{1, 0, 1, 1}};
    for (i = 0; i < 4; ++i)
        printf("%u\n", b.bits[i]);
    return 0;
}

我试着在结构乙声明位 为无符号整数位[4]： 1 或无符号整数位：1 [4] 或类似的东西都无济于事。我最好的猜测是，的typedef unsigned int类型位：1; ，并使用位作为类型，但仍然不的工作。

I tried declaring bits in struct B as unsigned int bits[4]:1 or unsigned int bits:1[4] or similar things to no avail. My best guess was to typedef unsigned int bit:1; and use bit as the type, yet still doesn't work.

我的问题是，这样的事可能吗？如果是的话，怎么样？如果不是，为什么不呢？ 1位无符号整数是一个有效的类型，那么为什么你不应该能够得到它的一个阵列？

My question is, is such a thing possible? If yes, how? If not, why not? The 1 bit unsigned int is a valid type, so why shouldn't you be able to get an array of it?

同样，我不想为此更换，我只是想知道这样的事情是如何可能的。

Again, I don't want a replacement for this, I am just wondering how such a thing is possible.

P.S。 ，我这个标记为C ++虽然code是用C写的，因为我假设的方法将两种语言存在。如果有一个C ++特定的方式做到这一点（通过使用语言结构，而不是库）我也有兴趣知道的。

P.S. I am tagging this as C++, although the code is written in C, because I assume the method would be existent in both languages. If there is a C++ specific way to do it (by using the language constructs, not the libraries) I would also be interested to know.

更新：我完全知道我能做到位操作自己。我在过去做了一千倍。我不感兴趣，说使用数组/向量，而不是做位操作一个答案。如果这个结构是可以或不可以，不可替代，我只是在想。

更新：答案为急躁（感谢neagoegab）：

Update: Answer for the impatient (thanks to neagoegab):

而不是

typedef unsigned int bit:1;

我可以使用

typedef struct
{
    unsigned int value:1;
} bit;

正确使用的#pragma包