减去两个datetime变量
如何获取两个日期时间变量之间的总小时数?
How can i get total number of hours between two datetime variable?
date1=1/1/2011 12:00:00
date2=1/3/2011 13:00:00
datetime date1 ;
datetime date2;
int hours=(date1.date2).hours;
输出为"1"，但我希望两个日期之间的总时差为49小时
the output is "1" but i want the total hour difference between two date i.e 49hours
谢谢
使用 小时 .请注意，结果是一个 double -您可以将其强制转换为 int 以获得整个小时数.(不过，如果结果为负，请检查您想要什么样的行为...)
Use TotalHours instead of Hours. Note that the result is a double - you can just cast it to int to get the whole number of hours. (Check what behaviour you want if the result is negative though...)
从文档中获取小时:
属性值:当前TimeSpan结构的小时部分.返回值的范围是-23到23
Property Value: The hour component of the current TimeSpan structure. The return value ranges from -23 through 23
您不需要小时 -您需要整个时间段，以小时为单位.
You don't want the hour component - you want the whole time span, expressed in hours.