Golang中的正则表达式：如何设置使字符串不匹配的字符？

问题描述：

I am a noob about regular expressions (sorry). I was trying to make a very simple markup language that matches bold and italic and then converts them to HTML. Here is an example for bold that I'm using:

var bold = regexp.MustCompile("\\*([^\\*]+)\\*")

It matches everything between two asterisks. Now, I'd like it to match *test* but not \*test*. Since I don't know much about regular expressions but I'm trying to make this experiment, I'd like to know what's the way for that. I searched everywhere but couldn't find the way to make this work.

我是有关正则表达式的菜鸟（对不起）。我正在尝试制作一种非常简单的匹配标记语言粗体和斜体，然后将它们转换为HTML。这是我正在使用的粗体示例： p>

  var粗体= regexp.MustCompile（“ \\ *（[  ^ \\ *] +）\\ *“）
  code>  pre> 
 
 它匹配两个星号之间的所有内容。 现在，我希望它匹配 * test *  code>，但不匹配 \ * test *  code>。 由于我对正则表达式了解不多，但我正在尝试进行此实验，所以我想知道这样做的方式。 我到处搜索，但找不到使这项工作有效的方法。 p> 
  div>

答

Updated

Go does not support lookbehinds. So a workaround can be:

(?:\A|(?:[^\\]+|\A)(\\{2})+|[^\\])\*([^\\*]+)\*

Golang中的正则表达式：如何设置使字符串不匹配的字符？

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