使用Jackson XML映射器将Java List序列化为XML

问题描述：

您好我需要使用Jackson-dataformat XMLMapper从JAVA创建XML。
XML应该像

Hi I need to create an XML from JAVA using Jackson-dataformat XMLMapper. The XML should be like

<Customer>
  <id>1</id>
  <name>Mighty Pulpo</name>
    <addresses>
      <city>austin</city>
      <state>TX</state>
    </addresses>
    <addresses>
      <city>*</city>
      <state>*</state>
    </addresses>
</Customer>

但我总是喜欢额外的< addresses>< / addresses>标签。

But I get it always like with an extra "< addresses> < /addresses>" tag.

<Customer>
  <id>1</id>
  <name>Mighty Pulpo</name>
<addresses>
    <addresses>
      <city>austin</city>
      <state>TX</state>
    </addresses>
    <addresses>
      <city>*</city>
      <state>*</state>
    </addresses>
<addresses>
</Customer>

我使用下面的代码创建XML

I am using below code to create XML

JaxbAnnotationModule jaxbAnnotationModule = new JaxbAnnotationModule();
XmlMapper mapper = new XmlMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT);
mapper.registerModule(jaxbAnnotationModule);
mapper.registerModule(new GuavaModule());
String xml = mapper.writeValueAsString(customer);
System.out.println(xml);

请帮助我一些人吗？如何删除额外的标签呢。我曾尝试使用@XmlElement，但它没有帮助。 TIA !!

Please can some one help me? How can I remove the extra tag please. I have tried to use @XmlElement but it does not help help. TIA!!

答

尝试以下代码

@JacksonXmlRootElement(localName = "customer") 
class Customer {

    @JacksonXmlProperty(localName = "id")
    private int id;
    @JacksonXmlProperty(localName = "name")
    private String  name;

    @JacksonXmlProperty(localName = "addresses")
    @JacksonXmlElementWrapper(useWrapping = false)
    private Address[] address;

    //getters, setters, toString
}

class Address {

    @JacksonXmlProperty(localName = "city")
    private String city;

    @JacksonXmlProperty(localName = "state")
    private String state;
    // getter/setter 
}

使用Jackson XML映射器将Java List序列化为XML

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