将 XML 反序列化为多个模式中定义的对象

我有一个 XML 文档，其中包含来自 2 个 XML 模式的类型.一个(他们的.xsd)是我正在与之集成(并且无法编辑)的专有模式.为此，我定义了自己的类型 (mine.xsd)，即any"元素中的元素是专有类型.

I have an XML document containing types from 2 XML schemas. One (theirs.xsd) is a proprietary schema that I am integrating with (and cannot edit). To do this I am defining my own type (mine.xsd) that is an element within an 'any' element is the proprietary type.

我使用 Visual Studio 的 xsd.exe 从架构生成 C# 类.但是，专有类型中的any"元素生成为 XmlElement[]，因此我的类型不会被反序列化.

I use Visual Studio's xsd.exe to generate C# classes from the schemas. However, the 'any' element in the proprietary type is generated as XmlElement[], and therefore my type doesn't get deserialized.

所以我想我可以采用以下两种方法之一:要么生成将我的类型反序列化而不是将其保留为 XmlElement 的类，要么采用 XmlElements 并单独反序列化它们.要反序列化我需要一个 XmlReader，所以我需要从一个 XmlElement 转到一个 XmlReader，我不知道该怎么做.谢谢.

So I guess I can go one of two ways: either generate classes that will deserialize my type rather then keeping it as an XmlElement, or take the XmlElements and deserialize them individually. To deserialize I need an XmlReader, so I would need to go from an XmlElement to an XmlReader which I'm not sure how to do. Thanks.

示例:文件:他们的.xsd

Example: File: theirs.xsd

<xs:element name="ProprietaryContainer">
  <xs:complexType>
    <xs:sequence>
      <xs:element name="name" type="xs:string"/>
      <xs:any namespace="##other" processContents="lax" minOccurs="0" maxOccurs="unbounded"/>
    </xs:sequence>
  </xs:complexType>
</xs:element>

文件:mine.xsd

File: mine.xsd

<xs:element name="MyPairType">
  <xs:complexType>
    <xs:sequence>
      <xs:element name="key" type="xs:string"/>
      <xs:element name="value" type="xs:long"/>
    </xs:sequence>
  </xs:complexType>
</xs:element>

文件:message.xml

File: message.xml

<their:ProprietaryContainer>
  <their:name>pairContainer</their:name>
  <mine:MyPairType>
    <mine:key>abc</mine:key>
    <mine:value>long</mine:value>
  </mine:MyPairType>
</their:ProprietaryContainer>