PHP按周数获取一周的开始和结束日期

问题描述：

我已经看到这个问题的一些变体，但我相信这个还没有被回答。

I've seen some variants on this question but I believe this one hasn't been answered yet.

我需要得到开始日期和结束日期一个星期，按年份和周数（不是日期）选择

I need to get the starting date and ending date of a week, chosen by year and week number (not a date)

示例：

input： p>

input:

getStartAndEndDate($week, $year);

输出：

$return[0] = $firstDay;
$return[1] = $lastDay;

返回值将是一个数组，其中第一个条目是星期开始日期，第二个是结束日期。

The return value will be something like an array in which the first entry is the week starting date and the second being the ending date.

可选：当我们在它时，日期格式需要是 Ynj 正常的日期格式，没有前导零。

OPTIONAL: while we are at it, the date format needs to be Y-n-j (normal date format, no leading zeros.

我已经尝试编辑现在的功能，几乎做了我想要的，但我迄今没有运气。

I've tried editing existing functions that almost did what I wanted but I had no luck so far.

请帮助我，谢谢提前。

答

function getStartAndEndDate($week, $year)
{

    $time = strtotime("1 January $year", time());
    $day = date('w', $time);
    $time += ((7*$week)+1-$day)*24*3600;
    $return[0] = date('Y-n-j', $time);
    $time += 6*24*3600;
    $return[1] = date('Y-n-j', $time);
    return $return;
}

PHP按周数获取一周的开始和结束日期

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