python:确定一个类是否嵌套

问题描述：

假设您有一个将类型作为参数的python方法；是否可以确定给定类型是否为嵌套类?
例如.在此示例中:

Suppose you have a python method that gets a type as parameter; is it possible to determine if the given type is a nested class?
E.g. in this example:

def show_type_info(t):
    print t.__name__
    # print outer class name (if any) ...

class SomeClass:
    pass

class OuterClass:
    class InnerClass:
        pass

show_type_info(SomeClass)
show_type_info(OuterClass.InnerClass)

我希望对show_type_info(OuterClass.InnerClass)的调用也能表明InnerClass是在OuterClass中定义的.

I would like the call to show_type_info(OuterClass.InnerClass) to show also that InnerClass is defined inside OuterClass.

答

AFAIK，给定一个类，但没有其他信息，则无法确定它是否为嵌套类.但是，请参见此处有关如何使用装饰器的信息确定这一点.

AFAIK, given a class and no other information, you can't tell whether or not it's a nested class. However, see here for how you might use a decorator to determine this.

问题在于，嵌套类只是普通类，是其外部类的属性.您可能希望使用的其他解决方案可能不会-例如，inspect.getmro仅提供基类，而不提供外部类.

The problem is that a nested class is simply a normal class that's an attribute of its outer class. Other solutions that you might expect to work probably won't -- inspect.getmro, for example, only gives you base classes, not outer classes.

此外，很少需要嵌套类.在每种您想使用它的特定情况下，我都会强烈考虑这是否是一种好方法.

Also, nested classes are rarely needed. I would strongly reconsider whether that's a good approach in each particular case where you feel tempted to use one.

python:确定一个类是否嵌套

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