如果不满足两个条件，则拒绝或循环遍历用户输入

问题描述：

我是Python的真正初学者，尽管到目前为止我都很喜欢它的每一分钟.

I am a real beginner with Python, although I am loving every minute of it so far.

我正在制作一个小程序，接受用户输入，然后对其进行处理.我的问题是用户输入的数字必须

I am making a little program that takes user input and then does stuff with it. My issue is that the numbers the user inputs have to

(1)全部加起来不超过一个(即a1 + a2 + a3 \ leq 1)

(1) All add up to not more than one (i.e. a1+ a2+ a3 \leq 1)

(2)分别为< 1.

(2) Each individually be < 1.

到目前为止，这是我的代码(仅是关键的中间部分):

Here is my code thus far (just the essential middle bit):

 num_array = list()


  a1  = raw_input('Enter percentage a (in decimal form): ')
  a2 = raw_input('Enter percentage b (in decimal form): ')
  ...
  an = raw_input('Enter percentage n (in decimal form): ')


li = [a1, a2, ... , an]

for s in li:
   num_array.append(float(s))

我很乐意构建一些东西，以使其要求用户在输入内容超出

And I would love to build in something to make it demand the user re-inputs things if their inputs either exceed the requirement that

a1 + a2 + a3> 1

a1+a2+a3 >1

或a1> 1，a2> 1，a3> 1等

or that a1>1, a2>1, a3>1 etc.

我觉得这真的很容易实现，但是由于我的知识有限，我被困住了！

I have a feeling this would be really easy to implement, but with my limited knowledge I am stuck!

任何帮助将不胜感激:-)

Any help would be much appreciated :-)

答

input_list = []
input_number = 1
while True:

    input_list.append(raw_input('Enter percentage {} (in decimal form):'.format(input_number))

    if float(input_list[-1]) > 1:     # Last input is larger than one, remove last input and print reason
        input_list.remove(input_list[-1])
        print('The input is larger than one.')
        continue

    total = sum([float(s) for s in input_list])
    if total > 1:    # Total larger than one, remove last input and print reason
        input_list.remove(input_list[-1])
        print('The sum of the percentages is larger than one.')
        continue

    if total == 1:    # if the sum equals one: exit the loop
        break

    input_number += 1

如果不满足两个条件，则拒绝或循环遍历用户输入

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