带有所需子解析器的 Argparse

我正在使用 Python 3.4，我正在尝试将 argparse 与子解析器一起使用，并且我想要与 Python 2.x 中的行为类似的行为，如果我不提供一个位置参数(指示子解析器/子程序)我会得到一个有用的错误消息.即，使用 python2 我将收到以下错误消息:

I'm using Python 3.4, I'm trying to use argparse with subparsers, and I want to have a similar behavior to the one in Python 2.x where if I don't supply a positional argument (to indicate the subparser/subprogram) I'll get a helpful error message. I.e., with python2 I'll get the following error message:

$ python2 subparser_test.py    
usage: subparser_test.py [-h] {foo} ...
subparser_test.py: error: too few arguments

我正在按照 https://stackoverflow.com/a/中的建议设置 required 属性22994500/3061818，但是这给了我 Python 3.4.0 的错误:TypeError: sequence item 0: expected str instance, NoneType found - full tr​​aceback:

I'm setting the required attribute as suggested in https://stackoverflow.com/a/22994500/3061818, however that gives me an error with Python 3.4.0: TypeError: sequence item 0: expected str instance, NoneType found - full traceback:

$ python3 subparser_test.py    
Traceback (most recent call last):
  File "subparser_test.py", line 17, in <module>
    args = parser.parse_args()
  File "/usr/local/Cellar/python3/3.4.0/Frameworks/Python.framework/Versions/3.4/lib/python3.4/argparse.py", line 1717, in parse_args
    args, argv = self.parse_known_args(args, namespace)
  File "/usr/local/Cellar/python3/3.4.0/Frameworks/Python.framework/Versions/3.4/lib/python3.4/argparse.py", line 1749, in parse_known_args
    namespace, args = self._parse_known_args(args, namespace)
  File "/usr/local/Cellar/python3/3.4.0/Frameworks/Python.framework/Versions/3.4/lib/python3.4/argparse.py", line 1984, in _parse_known_args
    ', '.join(required_actions))
TypeError: sequence item 0: expected str instance, NoneType found

这是我的程序 subparser_test.py - 改编自 https://docs.python.org/3.2/library/argparse.html#sub-commands:

This is my program subparser_test.py - adapted from https://docs.python.org/3.2/library/argparse.html#sub-commands:

import argparse

# sub-command functions
def foo(args):
    print('"foo()" called')

# create the top-level parser
parser = argparse.ArgumentParser()
subparsers = parser.add_subparsers()
subparsers.required = True

# create the parser for the "foo" command
parser_foo = subparsers.add_parser('foo')
parser_foo.set_defaults(func=foo)

args = parser.parse_args()
args.func(args)

相关问题:为什么此 argparse 代码在 Python 2 和 3 之间的行为不同?