如何在标签中对齐文本
问题描述:
我有一个标签显示在一行以上,我想说明其中的文本(左右对齐).最好的方法是什么?
I have a label that displays on more than a line and I would like to justify the text in it (align left and right). What is the best way to achieve that?
答
这是TaW提出的解决方案的实现.它只是实现的基本代码-无需自动重新调整等.
This is an implementation of the solution proposed by TaW. It is just the base code for the implementation - no automatic re-adjustments, etc.
public void Justify(System.Windows.Forms.Label label)
{
string text = label.Text;
string[] lines = text.Split(new[]{"\r\n"}, StringSplitOptions.None).Select(l => l.Trim()).ToArray();
List<string> result = new List<string>();
foreach (string line in lines)
{
result.Add(StretchToWidth(line, label));
}
label.Text = string.Join("\r\n", result);
}
private string StretchToWidth(string text, Label label)
{
if (text.Length < 2)
return text;
// A hair space is the smallest possible non-visible character we can insert
const char hairspace = '\u200A';
// If we measure just the width of the space we might get too much because of added paddings so we have to do it a bit differently
double basewidth = TextRenderer.MeasureText(text, label.Font).Width;
double doublewidth = TextRenderer.MeasureText(text + text, label.Font).Width;
double doublewidthplusspace = TextRenderer.MeasureText(text + hairspace + text, label.Font).Width;
double spacewidth = doublewidthplusspace - doublewidth;
//The space we have to fill up with spaces is whatever is left
double leftoverspace = label.Width - basewidth;
//Calculate the amount of spaces we need to insert
int approximateInserts = Math.Max(0, (int)Math.Floor(leftoverspace / spacewidth));
//Insert spaces
return InsertFillerChar(hairspace, text, approximateInserts);
}
private static string InsertFillerChar(char filler, string text, int inserts)
{
string result = "";
int inserted = 0;
for (int i = 0; i < text.Length; i++)
{
//Add one character of the original text
result += text[i];
//Only add spaces between characters, not at the end
if (i >= text.Length - 1) continue;
//Determine how many characters should have been inserted so far
int shouldbeinserted = (int)(inserts * (i+1) / (text.Length - 1.0));
int insertnow = shouldbeinserted - inserted;
for (int j = 0; j < insertnow; j++)
result += filler;
inserted += insertnow;
}
return result;
}
实际中: