一个分片只有一个名为list的元素，为什么subslice list [1:]可以工作?
问题描述：
一个切片只有一个名为list的元素，为什么subslice list [1:]可以工作? 例如:
A slice has only one element, named list, why can subslice list[1:] work? For example:
list := []int{1}
fmt.Println(list[1:])
fmt.Println(list[1])
列表中没有索引为1的元素，因此第三行会导致紧急:运行时错误:索引超出范围"，但是为什么第二行能正常工作呢?
The list hasn't the element with index 1, so the third line causes "panic: runtime error: index out of range", but why does the second line works well?
答
好，该语言只是定义这是有效的.
Well, the language simply defines this to be valid.
想想在细分中使用的索引指向元素之间":
Think of the indices used in subslicing as pointing "between" elements:
Slice a Elements: | 0 | 1 | 2 | 3 | 4 | 5 |
Subslice a[2:] ^===============
Subslice a[2:4] ^===========^
Subslice a[6:] ^
您的列表[1:]空片的片.
Your list[1:] slices of the empty slice.