如果字符串中包含点，则如何grep输入确切的单词
我试图在当前目录中搜索特定单词BML.I.
I was trying to search for a particular word BML.I in a current directory.
当我尝试使用以下命令时:
When I tried with the below command:
grep -l "BML.I" *
如果包含单词BML
是否可以对完全匹配的BML.I
Is it possible to grep for the exact match BML.I
您需要对进行转义. (句号)，因为默认情况下它会与任何字符匹配，并指定-w来匹配特定的单词，例如
You need to escape the . (period) since by default it matches against any character, and specify -w to match a specific word e.g.
grep -w -l "BML\.I" *
请注意，上面有两个转义级别.引号确保外壳程序将BML\.I传递给grep.然后\转义grep的句点.如果省略引号，则外壳程序会将\解释为该时间段的转义符(并将简单地将未转义的时间段传递给grep)
Note there are two levels of escaping in the above. The quotes ensure that the shell passes BML\.I to grep. The \ then escapes the period for grep. If you omit the quotes, then the shell interprets the \ as an escape for the period (and would simply pass the unescaped period to grep)