是否有正确的方法来$。扩展jQuery中的嵌套属性？

问题描述：

我拥有什么，我需要什么。这很容易。

What I have and what I need. It's easy.

默认选项（有嵌套属性）：

The default options (there are nested properties):

{
  sDom: 'frt<"tfoot"lp>',
  bInfo: false,
  sPaginationType: "full_numbers",
  oLanguage: {
    sSearch: "",
    sLengthMenu: "Show _MENU_",
    oPaginate: {
      sFirst:     "|<<",
      sLast:      ">>|",
      sNext:      ">>",
      sPrevious:  "<<"
    }
  }
}

实际期权：

{
  oLanguage: {
    oPaginate: {
      sNext:      "MODIFIED"
    }
  }
}

$ .extend的结果：

The result of $.extend:

{
  sDom: 'frt<"tfoot"lp>',
  bInfo: false,
  sPaginationType: "full_numbers",
  oLanguage: {
    oPaginate: {
      sNext:      "MODIFIED"
    }
  }
}

我需要的是使用实际选项正确扩展默认选项并获得以下结果（一个属性已被修改）：

What I need is to properly extend the defaults options with the actual options and get the following result (one property has been modified):

{
  sDom: 'frt<"tfoot"lp>',
  bInfo: false,
  sPaginationType: "full_numbers",
  oLanguage: {
    sSearch: "",
    sLengthMenu: "Show _MENU_",
    oPaginate: {
      sFirst:     "|<<",
      sLast:      ">>|",
      sNext:      "MODIFIED"
      sPrevious:  "<<"
    }
  }
}

问题是$。 extend函数忽略嵌套属性并仅操作第一级属性。现在我手动$ .extend每个嵌套属性，但我想这不是解决方案。

The problem is that $.extend function ignores nested properties and operates only first-level properties. Now I have manually $.extend each of the nested properties, but I guess it is not a solution.

答

你需要递归副本，将 true 作为第一个参数传递：

You need a recursive copy by passing true as the first parameter:

var defaults = {...}
var actual = {...}

//recursively merge to a blank object
console.log($.extend(true,{}, defaults, actual))

是否有正确的方法来$。扩展jQuery中的嵌套属性？

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