java:进行列表深度复制的最佳方法

问题描述：

我正在尝试编写一个程序来做List<List<Integer>>的深层复制，并且我这样做是这样的:

I am trying to write a procedure do the deep copy of List<List<Integer>>, and I am doing like this:

public static List<List<Integer>> clone(final List<List<Integer>> src)
{
    List<List<Integer>> dest = new ArrayList<List<Integer>>();
    for( List<Integer> sublist : src) {
        List<Integer> temp = new ArrayList<Integer>();
        for(Integer val: sublist) {
            temp.add(val);
        }
        dest.add(temp);
    }
    return dest ;
}

这是一个好方法吗?是否有可能摆脱内循环?事实是，每个内部子列表都可以增长很大的长度.

Is this a good way to do? Is it possible to get rid of the inner loop? The fact is that each of the inner sub-lists can grow to large lengths.

答

这是一个好方法吗?

Is this a good way to do?

很好.

是否有可能摆脱内循环?

Is it possible to get rid of the inner loop?

是的，您可以使用ArrayList复制构造函数:

Yes, you can use the ArrayList copy constructor:

for( List<Integer> sublist : src) {
    dest.add(new ArrayList<>(sublist));
}

事实是，每个内部子列表都可以增长很大的长度.

The fact is that each of the inner sub-lists can grow to large lengths.

上面的代码将缩短代码，并将其委派给System.arraycopy，这可能会在某种程度上提高性能.当您填充空的ArrayList时，它还避免了重复的调整大小/复制操作.但是，如果您确实需要深层复制，从根本上讲，没有办法避免复制列表/数组的O(n)时间复杂性.由于您不解释为什么，因此需要详细的副本，因此，我将一字不漏.

The above will shorten the code, and it delegates to System.arraycopy, which will likely improve performance somewhat. It also avoids the repeated resize/copy when you fill an empty ArrayList. But there's fundamentally no way to avoid the O(n) time complexity of copying a list/array, if you truly need a deep copy. Since you don't explain why you need a deep copy, I'll have to take you at your word.

java:进行列表深度复制的最佳方法

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