深度克隆（复制）可变的Scala对象的最简单方法是什么？
问题描述：
深度克隆（复制）可变的Scala对象的最简单方法是什么？
What is the easiest way to deeply clone (copy) a mutable Scala object?
答
因为您想要最简单的方法要深度复制Scala对象而不是最快的对象，您可以始终序列化该对象（前提是该对象可序列化），然后反序列化它。以下代码仅在编译时运行，而不是在REPL中运行。
Since you want the easiest way to deep copy a Scala object and not the fastest, you can always serialize the object, provided that it's serializable, and then deserialize it back. The following code only runs when compiled, not in REPL.
def deepCopy[A](a: A)(implicit m: reflect.Manifest[A]): A =
util.Marshal.load[A](util.Marshal.dump(a))
val o1 = new Something(...) // "Something" has to be serializable
val o2 = deepCopy(o1)