在C中更新时间表

问题描述：

该功能将按时添加

如果相同时间的重复描述将返回false

the function will add on schedule

if a duplicate description with same timing it will return false

bool add_new_appointment(
                         struct Appointment schedule[],
                         int numOfAptInSchedule,
                         char description[],
                         int year, int month, int day,
                         int startHour, int startMinute,
                         int endHour, int endMinute )
{
    
    return false;
}

我的尝试：

What I have tried:

struct Appointment {
    char description[50];
    int year;
    int month;
    int day;
    int startHour;
    int startMinute;
    int endHour;
    int endMinute;
};

<pre>void print_schedule( struct Appointment schedule[], int numOfAptInSchedule )
{
    printf("\nAppointment: %d\n%d-%d-%d\n%s\n%.2d:%.2d to %.2d:%.2d\n\n",
           numOfAptInSchedule,
           schedule->year,schedule->month, schedule->day,
           schedule->description,
           schedule->startHour,schedule->startMinute,
           schedule->endHour,schedule->endMinute);
}

int main(){

    struct Appointment mySchedule[20];
    int numAptInSchedule = 0;
    
    
     if ( add_new_appointment( mySchedule, numAptInSchedule,
     "Train with Luke",
     2018, 1, 28, 9, 0, 11, 30)){
     numAptInSchedule++;
     printf("Appointment added!\n");
     print_schedule( mySchedule, numAptInSchedule);
     }
}

答

这应该是微不足道的，假设传递之间有一对一的对应关系参数和 struct Appointment 成员（你没有提供有关的信息）

That should be trivial, assuming there is one-by-one correspondence between passed parameters and struct Appointment members (you didn't provide info about)

  bool add_new_appointment(
                         struct Appointment schedule[],
                         int numOfAptInSchedule,
                         char description[],
                         int year, int month, int day,
                         int startHour, int startMinute,
                         int endHour, int endMinute )
{
  struct Appointment *pa = &schedule[numOfAptInSchedule]; // just an alias

  // assuming struct Appointment.description is a character array 
  size_t size = sizeof(pa->description);
  strncpy( pa->description, description, size - 1); 
  pa->description[size-1] = '\0';
  pa->year = year;
  pa->month = month;
  //..
  return true;
}

请注意：错误检查留作练习。

Please note: error checking left as exercise.

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