用collection.sort（）步骤对list集合排序

用collection.sort（）方法对list集合排序

第一种是list中的对象实现Comparable接口，如下：

/** 
* 根据order对User排序 
*/ 
public class User implements Comparable<User>{ 
    private String name; 
    private Integer order; 
    public String getName() { 
        return name; 
    } 
    public void setName(String name) { 
        this.name = name; 
    } 
    public Integer getOrder() { 
        return order; 
    } 
    public void setOrder(Integer order) { 
        this.order = order; 
    } 
    public int compareTo(User arg0) { 
        return this.getOrder().compareTo(arg0.getOrder()); 
    } 
}

测试一下：

public class Test{

    public static void main(String[] args) { 
        User user1 = new User(); 
        user1.setName("a"); 
        user1.setOrder(1); 
        User user2 = new User(); 
        user2.setName("b"); 
        user2.setOrder(2); 
        List<User> list = new ArrayList<User>(); 
        //此处add user2再add user1 
        list.add(user2); 
        list.add(user1); 
        Collections.sort(list); 
        for(User u : list){ 
            System.out.println(u.getName()); 
        } 
    } 
}

输出结果如下
a
b

第二种方法是根据Collections.sort重载方法来实现，例如：

/** 
* 根据order对User排序 
*/ 
public class User { //此处无需实现Comparable接口 
    private String name; 
    private Integer order; 
    public String getName() { 
        return name; 
    } 
    public void setName(String name) { 
        this.name = name; 
    } 
    public Integer getOrder() { 
        return order; 
    } 
    public void setOrder(Integer order) { 
        this.order = order; 
    } 
}

主类中这样写即可：

public class Test{ 
    public static void main(String[] args) { 
        User user1 = new User(); 
        user1.setName("a"); 
        user1.setOrder(1); 
        User user2 = new User(); 
        user2.setName("b"); 
        user2.setOrder(2); 
        List<User> list = new ArrayList<User>(); 
        list.add(user2); 
        list.add(user1); 
        
        Collections.sort(list,new Comparator<User>(){ 
            public int compare(User arg0, User arg1) { 
                return arg0.getOrder().compareTo(arg1.getOrder()); 
            } 
        }); 
        for(User u : list){ 
            System.out.println(u.getName()); 
        } 
    } 
}

输出结果如下
a
b
前者代码结构简单，但是只能根据固定的属性排序，后者灵活，可以临时指定排序项，但是代码不够简洁

多字段的场合：
Collections.sort(list,new Comparator<User>(){
            public int compare(User arg0, User arg1) {
//            第一次比较专业
                int i = arg0.getOrder().compareTo(arg1.getOrder());

//            如果专业相同则进行第二次比较
            if(i==0){
//                第二次比较
                int j=arg0.getXXX().compareTo(arg1.getXXX());
//                如果学制相同则返回按年龄排序
                if(j==0){
                    return arg0.getCCC().compareTo(arg1.getCCC());
                }
                return j;
            }
            return i;
            }
        });

以下是另外一个例子
package test;

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;

public class ArrayListTest {
public static void main(String[] args) {
ArrayList<Exmployee> arrayList = new ArrayList<Exmployee>() ;
arrayList.add(new Exmployee("zengqiang",new Integer(5000))) ;
arrayList.add(new Exmployee("zengmin",new Integer(4000))) ;
arrayList.add(new Exmployee("liuxiaojuan",new Integer(4200))) ;
arrayList.add(new Exmployee("giuming",new Integer(2200))) ;
Collections.sort(arrayList, new Comparator<Exmployee>(){
public int compare(Exmployee arg0, Exmployee arg1) {
return arg1.getSalary()-arg0.getSalary() ; //按照工资升序
//return arg0.getSalary()-arg1.getSalary() ; 按照工资降序
//return arg0.getName().compareTo(arg1.getName()) ; 按照姓名升序
}
});
for(Exmployee e:arrayList)
System.out.println(e.getName()+"'s salary is "+e.getSalary()) ;
}

}

class Exmployee {
public Exmployee(String name, int salary) {
this.name = name ;
this.salary = salary ;
}

private String name;

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public int getSalary() {
return salary;
}

public void setSalary(int salary) {
this.salary = salary;
}

private int salary;
}

用collection.sort（）步骤对list集合排序

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