为什么我无法检索从反引号内部暂停的程序?

问题描述:

我创建了一个程序,该程序使用参数列表并将其放在新tty的网格中,我可以在其中移动并从中选择所需的内容.

I created a program that takes a list of arguments and put them in a grid on a new tty where I can move around and select from it what I want.

当我运行程序时没有这样的反引号...

When I run the program without backticks like this...

$> ./ft_select arg_1 arg_2 ... arg_N

打开一个新的tty并显示一个网格...

A new tty is opened and a grid is shown...

arg_1  arg_2  arg_3
arg_4  arg_5  arg_6
arg_7  ...    arg_N

我按 ctrl + z ,程序被挂起没有问题,并且fg命令将其放回.

I hit ctrl+z and the program gets suspended with no problem and fg command puts it back.

我的问题是,当我在反引号之间放置命令并尝试挂起它时,它卡住了而没有给出提示.

My problem is that when I put the command between backticks and I try to suspend it, it get stuck without giving the prompt back.

我不得不提到我将网格的所有内容写在/dev/tty

I have to mention that I write all the content of the grid on /dev/tty

您可以在下面的代码中找到执行信号处理的功能.

You can find in the code below the function that does the signal handling.

 23 void    signalhandler(int sig)
 24 {
 25 //  struct winsize  ws;
 26
 27     if (sig == SIGWINCH)
 28     {
 29 //      ioctl(g_data->tty, TIOCGWINSZ, &ws);
 30         update_data(g_data);
 31         print_args(g_data);
 32         update_cursor(g_data, 1);
 33     }
 34     else if (sig == SIGTSTP)
 35     {
 36         signal(SIGTSTP, SIG_DFL);
 37         enable_cap("te");
 38         modify_main_caps(SET, g_data->tty);
 39         ioctl(g_data->tty, TIOCSTI, "\032");
 40     }
 41     else if (sig == SIGCONT)
 42     {
 43         signal(SIGTSTP, signalhandler);
 44         modify_main_caps(UNSET, g_data->tty);
 45         update_data(g_data);
 46         print_args(g_data);
 47         update_cursor(g_data, 1);
 48     }
 49     else if (sig == SIGINT)
 50     {
 51         enable_cap("te");
 52         modify_main_caps(SET, g_data->tty);
 53         exit(EXIT_FAILURE);
 54     }
 55 }

CTRL + Z 导致终端设备驱动程序将SIGTSTP发送到前台进程组.至少在bashzsh中,命令替换$(<command>)中的命令在子shell中执行,但是它们没有得到自己的进程组(它们在同一进程中运行)组作为父外壳本身).这意味着 CTRL + Z 完全不会影响它们-按下它并没有任何反应,就像按下 CTRL + Z 在shell提示符下什么也不做:在两种情况下,都没有要挂起的前台进程组!

CTRL+Z causes the terminal device driver to send a SIGTSTP to all processes in the foreground process group. In bash and zsh, at least, commands in a command substitution $(<command>) are executed in a subshell, but they don't get their own process group (they run in the same process group as the parent shell itself). That means that CTRL+Z should not affect them at all - press it and nothing happens, just like pressing CTRL+Z in a shell prompt doesn't do anything: in both cases, there is no foreground process group to suspend!