如果全部在列表中 == 某物
问题描述：
使用 Python 2.6，有没有办法在一个语句中检查序列的所有项是否等于给定值?
Using Python 2.6, is there a way to check if all the items of a sequence equals a given value, in one statement?
[pseudocode]
my_sequence = (2,5,7,82,35)
if all the values in (type(i) for i in my_sequence) == int:
do()
而不是说:
my_sequence = (2,5,7,82,35)
all_int = True
for i in my_sequence:
if type(i) is not int:
all_int = False
break
if all_int:
do()
答
使用:
all( type(i) is int for i in lst )
示例:
In [1]: lst = range(10)
In [2]: all( type(i) is int for i in lst )
Out[2]: True
In [3]: lst.append('steve')
In [4]: all( type(i) is int for i in lst )
Out[4]: False
.根据评论变得更干净.
. Made cleaner as per comments.