在 Python 中使用变量作为传递给 **kwargs 的关键字
我有一个通过 API 更新记录的函数.API 接受各种可选的关键字参数:
I have a function that updates a record via an API. The API accepts a variety of optional keyword parameters:
def update_by_email(self, email=None, **kwargs):
result = post(path='/do/update/email/{email}'.format(email=email), params=kwargs)
我有另一个函数,它使用第一个函数来更新记录中的单个字段:
I have another function that uses the first function to update an individual field in the record:
def update_field(email=None, field=None, field_value=None):
"""Encoded parameter should be formatted as <field>=<field_value>"""
request = update_by_email(email=email, field=field_value)
这不起作用.当我打电话时:
This doesn't work. When I call:
update_field(email='joe@me.com', field='name', field_value='joe')
网址编码为:
https://www.example.com/api/do/update/email/joe@me.com?field=Joe
我怎样才能让它编码为:
How can I get it to encode as:
https://www.example.com/api/do/update/email/joe@me.com?name=Joe
提前致谢.
与其传递名为field
的参数,不如使用字典解包来使用的值field
作为参数的名称:
Rather than passing the parameter named as field
, you can use dictionary unpacking to use the value of field
as the name of the parameter:
request = update_by_email(email, **{field: field_value})
使用 update_by_email
的模拟:
def update_by_email(email=None, **kwargs):
print(kwargs)
当我打电话时
update_field("joe@me.com", "name", "joe")
我看到 update_by_email
里面的 kwargs
是
I see that kwargs
inside update_by_email
is
{'name': 'joe'}