检查用户是否在浏览器会话中访问过网站

问题描述：

所以我有这个初始屏幕动画，当你访问我的网站。然而，我只想要动画播放第一次你访问它（在会话当然）。我试图做一个if else，我检查一个cookie称为会话，如果存在，删除包含动画的div。如果没有此类Cookie，请创建它。

So I have this splash screen animation that plays when you visit my website. However, I only want the animation to play the first time you visit it (in the session of course). I tried to make an if else where I check for a cookie called "Session", and if it exists, delete the div containing the animation. If there is no such cookie, create it.

代码：

function session() {
    if (document.cookie.indexOf("visited") >= 0) {
        $('.splash').remove(this);
    } else {
        document.cookie = "visited";
    }
}

我从来没有使用过cookies，所以我想我可能发生了一些错误

I have never used cookies before so I think I might have made some errors

答

代码中处理cookie的部分应该可以正常工作。

The portion of your code that deals with cookies should work.

您的问题存在于此行上：

Your problem exists on this line:

$('.splash').remove(this);

删除此，因为没有必要。

Remove this, as it's not necessary.

该行应如下所示：

$('.splash').remove();

希望有帮助。

检查用户是否在浏览器会话中访问过网站

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