.NET XML序列化 - 存储引用,而不是对象的副本
问题描述:
- 在净/ C#应用程序,我有数据结构具有相互之间的引用。
- 当我序列化它们,净序列化与独立的对象副本的所有引用。
- 在以下示例中,我试图序列化到'人' 数组
-
人可能会参考其他人。
- In .Net/C# Application, I have data structures which have references to each other.
- When I serialize them, .Net Serializes all references with separate object copies.
- In Following Example, I am trying to serialize to Array of 'Person'
A 'Person' may have reference to another person.
public class Person
{
public string Name;
public Person Friend;
}
Person p1 = new Person();
p1.Name = "John";
Person p2 = new Person();
p2.Name = "Mike";
p1.Friend = p2;
Person[] group = new Person[] { p1, p2 };
XmlSerializer ser = new XmlSerializer(typeof(Person[]));
using (TextWriter tw = new StreamWriter("test.xml"))
ser.Serialize(tw,group );
//above code generates following xml
<ArrayOfPerson>
<Person>
<Name>John</Name>
<Friend>
<Name>Mike</Name>
</Friend>
</Person>
<Person>
<Name>Mike</Name>
</Person>
</ArrayOfPerson>
在上面code,同样的'迈克'的对象是有两个地方,因为是同一个对象的两个引用。
答
这是不可能的XmlSerializer.你可以做到这一点与DataContractSerializer使用$p$pserveObjectReferences属性。你可以看看这个帖子这解释了细节。
It is not possible with XmlSerializer. You could achieve this with DataContractSerializer using the PreserveObjectReferences property. You may take a look at this post which explains the details.
下面是一个示例code:
Here's a sample code:
public class Person
{
public string Name;
public Person Friend;
}
class Program
{
static void Main(string[] args)
{
Person p1 = new Person();
p1.Name = "John";
Person p2 = new Person();
p2.Name = "Mike";
p1.Friend = p2;
Person[] group = new Person[] { p1, p2 };
var serializer = new DataContractSerializer(group.GetType(), null,
0x7FFF /*maxItemsInObjectGraph*/,
false /*ignoreExtensionDataObject*/,
true /*preserveObjectReferences : this is where the magic happens */,
null /*dataContractSurrogate*/);
serializer.WriteObject(Console.OpenStandardOutput(), group);
}
}
这将产生以下XML:
This produces the following XML:
<ArrayOfPerson z:Id="1" z:Size="2" xmlns="http://schemas.datacontract.org/2004/07/ToDelete" xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:z="http://schemas.microsoft.com/2003/10/Serialization/">
<Person z:Id="2">
<Friend z:Id="3">
<Friend i:nil="true"/>
<Name z:Id="4">Mike</Name>
</Friend>
<Name z:Id="5">John</Name>
</Person>
<Person z:Ref="3" i:nil="true"/>
</ArrayOfPerson>
现在设置 preserveObjectReferences
到假
在构造函数中,你会得到这样的:
Now set PreserveObjectReferences
to false
in the constructor and you will get this:
<ArrayOfPerson xmlns="http://schemas.datacontract.org/2004/07/ToDelete" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<Person>
<Friend>
<Friend i:nil="true"/>
<Name>Mike</Name>
</Friend>
<Name>John</Name>
</Person>
<Person>
<Friend i:nil="true"/>
<Name>Mike</Name>
</Person>
</ArrayOfPerson>
值得一提的是,这种方式生产的XML是不能互通的,只能用DataContractSerializer的(同样的评论被反序列化的BinaryFormatter).