如何在 symfony2 全局辅助函数(服务)中访问服务容器?

这个问题开始时我不明白为什么我不能将变量传递给 symfony2 全局辅助函数(服务)，但多亏了比我聪明的人，我意识到我的错误是试图从内部使用 security_context没有注入它的类所以...

This question started out with me not understanding why I couldn't pass variables to a symfony2 global helper function (service), but thanks to people brighter than I, I realized my error was about trying to use the security_context from within a class that didn't have it injected so...

这是最终的结果，有效的代码.我发现没有更好的方法可以让这对社区有所帮助.

This is the final result, the code that works. I found no better way of making this helpful to the comunity.

这是您如何从 symfony2 中的全局函数或辅助函数中的 security_context 中获取用户和其他数据的方法.

This is how you can get the user and other data from security_context from within a global function or helper function in symfony2.

我有以下类和函数:

<?php
namespace BizTVCommonBundleHelper;

use SymfonyComponentDependencyInjectionContainerInterface as Container;

class globalHelper {    

private $container;

public function __construct(Container $container) {
    $this->container = $container;
}   

    //This is a helper function that checks the permission on a single container
    public function hasAccess($container)
    {
        $user = $this->container->get('security.context')->getToken()->getUser();

        //do my stuff
    }     
}

...定义为这样的服务(在 app/config/config.yml 中)...

...defined as a service (in app/config/config.yml) like this...

#Registering my global helper functions            
services:
  biztv.helper.globalHelper:
    class: BizTVCommonBundleHelperglobalHelper
    arguments: ['@service_container']

现在，在我的控制器中，我像这样调用这个函数......

Now, in my controller I call on this function like this...

public function createAction($id) {

    //do some stuff, transform $id into $entity of my type...

    //Check if that container is within the company, and if user has access to it.
    $helper = $this->get('biztv.helper.globalHelper');
    $access = $helper->hasAccess($entity);