SSH无法通过PHP exec正常工作
Hey I'm attempting to utilise the PHP SSH2 functions of which I've used a class from over a GitHub: Here but doesn't seem to be working as expected.
I'm trying to cd
into a directory and then list files, but seems to ignore the cd
and when I use the ls
command it just displays the root dir.
Here's when I perform a normal ls
on my root directory:
drwx------ 6 root root 4096 Aug 12 18:23 .
drwxr-xr-x 22 root root 4096 Aug 11 08:28 ..
-rw------- 1 root root 2963 Aug 12 18:33 .bash_history
-rw-r--r-- 1 root root 3106 Oct 22 2015 .bashrc
drwx------ 3 root root 4096 Aug 11 21:05 .cache
drwxr-xr-x 3 root root 4096 Aug 12 18:21 .local
drwxr-xr-x 2 root root 4096 Aug 12 18:22 .nano
drwxr-xr-x 18 root root 4096 Aug 11 21:07 myOtherDirectory
-rw-r--r-- 1 root root 148 Aug 17 2015 .profile
-rw------- 1 root root 1024 Aug 12 18:27 .rnd
-rw-r--r-- 1 root root 252 Aug 12 18:28 .wget-hsts
And here's then I try to access the myOtherDirectory
using SSH via PHP
$ssh = new ssh("ip", "root", "pass");
$ssh("cd myOtherDirectory");
$result = $ssh("ls -la");
print_r($result);
嘿我正在尝试利用PHP SSH2函数,我在GitHub上使用了一个类: 此处但似乎没有按预期工作。 p>
我正在尝试 这是我在根目录下执行普通 然后我尝试通过PHP使用SSH访问 cd code>到一个目录然后列出文件,但似乎忽略了
cd code>,当我使用
ls code>命令时它只是 显示根目录。 p>
ls code>的时候: p>
drwx ------ 6 root root 4096 Aug 12 18:23。
drwxr-xr-x 22 root root 4096 Aug 11 08:28 ..
-rw ------- 1 root root 2963 Aug 12 18:33 .bash_history
-rw-r - r-- 1 root root 3106 Oct 22 2015 .bashrc
drwx ------ 3 root root 4096 Aug 11 21:05 .cache
drwxr-xr-x 3 root root 4096 Aug 12 18:21 .local
drwxr-xr-x 2 root root 4096 Aug 12 18:22 .nano
drwxr-xr-x 18 root root 4096 Aug 11 21:07 myOtherDirectory
-rw-r --r-- 1 root root 148 Aug 17 2015 .p rofile
-rw ------- 1 root root 1024 Aug 12 18:27 .rnd
-rw-r - r-- 1 root root 252 Aug 12 18:28 .wget-hsts
pre>
myOtherDirectory code> p>
$ ssh = new ssh(“ip”,“root”,“pass”);
$ ssh(“cd myOtherDirectory”);
$ result = $ ssh(“ls -la”);
print_r($ result);
code> pre>
div>
The SSH protocol permits you to make one SSH connection (called a session) to a remote host and then run multiple channels through the single connection. A single channel can represent an interactive session, a single SFTP transfer, and so on. Each channel is independent of the others.
$ssh = new ssh("ip", "root", "pass");
$ssh("cd myOtherDirectory");
$result = $ssh("ls -la");
What you're doing here is creating a single SSH session to the remote host, then creating two channels. The first channel runs cd
and then exits. The second channel runs ls
and then exits. The two channels are independent of each other, so the cd
invocation has no effect on the working directory of the ls
invocation.
You want to run both commands in a single session. Assuming the remote system is using bash
or a similar shell to run commands, this ought to work:
$ssh = new ssh("ip", "root", "pass");
$result = $ssh("cd myOtherDirectory && ls -la");
Alternately, you could specify the correct remote directory in the ls
command:
$ssh = new ssh("ip", "root", "pass");
$result = $ssh("ls -la myOtherDirectory");