按长度对字符串的 ArrayList 进行排序

问题描述：

我想按长度对字符串的 ArrayList 进行排序，而不仅仅是按数字顺序.

I want to order an ArrayList of strings by length, but not just in numeric order.

例如，列表包含以下单词:

Say for example, the list contains these words:

cucumber
aeronomical
bacon
tea
telescopic
fantasmagorical

它们需要按照长度的不同排序为一个特殊的字符串，例如:

They need to be ordered by their difference in length to a special string, for example:

intelligent

所以最终列表看起来像这样(括号中的差异):

So the final list would look like this (difference in brackets):

aeronomical     (0)
telescopic      (1)
fantasmagorical (3) - give priority to positive differences? doesn't really matter
cucumber        (3)
bacon           (6)
tea             (8)

答

使用自定义比较器:

public class MyComparator implements java.util.Comparator<String> {

    private int referenceLength;

    public MyComparator(String reference) {
        super();
        this.referenceLength = reference.length();
    }

    public int compare(String s1, String s2) {
        int dist1 = Math.abs(s1.length() - referenceLength);
        int dist2 = Math.abs(s2.length() - referenceLength);

        return dist1 - dist2;
    }
}

然后使用 java.util.Collections.sort(List, Comparator) 对列表进行排序.

Then sort the list using java.util.Collections.sort(List, Comparator).

按长度对字符串的 ArrayList 进行排序

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