如何使用PHP - YouTube API从XML文件中检索内容

问题描述：

Please help in using PHP and XML in retrieving dynamic content.

I have this code:

function yt_name() {
$xmlData = file_get_contents( 'http://gdata.youtube.com/feeds/api/users/youtube/uploads?max-results=5&prettyprint=true' ); 
$xml = new SimpleXMLElement($xmlData); 
$yt_name = $xml->event->name;

    echo $yt_name;

}

How can I retrieve the content inside <name>content</name> ?

Regards,

Thank you!

请帮助您在检索动态内容时使用PHP和XML。 p>

I 有这段代码： p>

  function yt_name（）{
 $ xmlData = file_get_contents（'http://gdata.youtube.com/feeds/api/users/youtube/uploads  ？max-results = 5＆amp; prettyprint = true'）;  
 $ xml = new SimpleXMLElement（$ xmlData）;  
 $ yt_name = $ xml-＆gt; event-＆gt; name; 
 
 echo $ yt_name; 
 
} 
  code>  pre> 
 
 如何检索 ＆lt; name＆gt; content＆lt; / name＆gt;  code>里面的内容？ p> 
 
 
问候， p> 
 
 

谢谢！ p  > 
  div>

答

Once inside the object, you can retrieve childs by object index (node name):

function yt_name() {
    $xmlData = file_get_contents( 'http://gdata.youtube.com/feeds/api/users/youtube/uploads?max-results=5&prettyprint=true' ); 
    $xml = new SimpleXMLElement($xmlData); 
    return $xml;
}

$yt = yt_name();
echo $yt->author->name;

Output: YouTube Spotlight

答

I'm not sure what your XML format looks like, but something like this should work -

$XMLData =
"<?xml version='1.0' encoding='UTF-8'?>
<video>
<name>This is the name</name>
<submitter>Mrs. Robinson</submitter>
</video>";

$xml=simplexml_load_string($XMLData) or die("Error");


echo $xml->name;

答

Don't use this anymore V2 API is deprecated since april 2014 and will be closed on 21 april 2015

Use the json V3 API https://developers.google.com/youtube/v3/

如何使用PHP - YouTube API从XML文件中检索内容

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